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3 years ago

Puzzle 3

Physics

1 answer:

Hunter-Best [27]3 years ago

4 0

Answer:

hagcsgdufgeuwuwgsgwhajisydcbeek

Explanation:

edowooooooww

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Considera que en tu casa tienes un televisor de 110 W, si pasa encendido 4 horas diarias, Cuál será la energía consumida durante

rjkz [21]

Answer:

E = 13.2 kWh

, Cost = $ 10.8

Explanation:

We can look for the consumed energy from the expression of the power

P = W / t

The work is equal to the variation of the kinetic energy, for which

P = E / t

E = P t

look for the energy consumed in one day and multiply by the days of the month in the month

E = 110 4 30

E = 13200 W h

E = 13.2 kWh

the cost of this energy is

Cost = 0.9 12

Cost = $ 10.8

4 0

3 years ago

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A hollow cylinder of mass 2.00 kg, inner radius 0.100 m, and outer radius 0.200 m is free to rotate without friction around a ho

Aneli [31]

Answer:

h=2.86m

Explanation:

In order to give a quick response to this exercise we will use the equations of conservation of kinetic and potential energy, the equation is given by,

$\Delta PE_i + \Delta KE_i = \Delta PE_f +\Delta KE_f$

There is no kinetic energy in the initial state, nor potential energy in the end,

$mgh+0=0+KE_f$

In the final kinetic energy, the energy contributed by the Inertia must be considered, as well,

$mgh = (\frac{1}{2}mv^2+\frac{1}{2}I\omega^2)$

The inertia of the bodies is given by the equation,

$I=\frac{m(R_1^2+R^2_2)}{2}$

$I=\frac{2(0.2^2+0.1^2)}{2}$

$I=0.05Kgm^2$

On the other hand the angular velocity is given by

$\omega =\frac{v}{R_2}=\frac{4}{1/5} = 2rad/s$

Replacing these values in the equation,

$(0.5)(9.8)(h) =\frac{1}{2}*0.5*4^2+\frac{1}{2}*0.05*20^2$

Solving for h,

$h=2.86m$

5 0

3 years ago

Now our wavelength is getting longer

aleksley [76]

This makes frequency lower as well as the pitch we hear.

6 0

3 years ago

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A=vf-vi/t is the equation for calculating the acceleration of an object. write out the relationship shown in the equation using

Lelechka [254]

Basically it is the difference in velocity divided by the time it takes to make that change.

3 0

3 years ago

A parallel-plate capacitor in air has a plate separation of 1.76 cm and a plate area of

Monica [59]

Answer:

Explanation:

Plate separation, d = 1.76 cm = 0.0176 m

Area of plates, A = 25 cm^2 = 0.0025 m^2

V = 255 V

(a) Capacitance of capacitor

$C = \frac{\epsilon _0A}{d}$

$C = \frac{8.854\times 10^{-12}\times 0.0025}{0.0176}$

C = 1.258 x 10^-12 F

charge is same before and after immersion as the battery is disconnected

q = C V

q = 1.258 x 10^-12 x 255 = 3.2 x 10^-10 C

(b)

Capacitance before, C = 1.258 x 10^-12 C

capacitance after, C' = k x C = 80 x 1.258 x 10^-12 = 100.64 x 10^-12 C

Where, k is the dielectric constant of water = 80

Potential difference after immersion, V' = V / k = 255 / 80 = 3.1875 V

$U = \frac{q^{2}}{2C}$

$U = \frac{(3.2\times 10^{-10})^{2}}{2\times 1.258\times 10^{-12 }}=4.07\times 10^{-8}J$

Final energy

$U' = \frac{q^{2}}{2C'}$

$U' = \frac{(3.2\times 10^{-10})^{2}}{2\times 100.64\times 10^{-12}}=5.08\times 10^{-10}J$

6 0

3 years ago