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3 years ago

14

describe the motion of a pendulum in terms of kinetic and potential energy when it goes from its highest point to lowest point,

how would the energy change?

1 answer:

MatroZZZ [7]3 years ago

4 0

When it reaches it's peak, the energy is converted into potential as it slows down, then back to kinetic as it goes back to the lowest point.

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What is air temperature meausered with?

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Temperature is usually expressed in degrees Fahrenheit or Celsius. 0 degrees Celsius is equal to 32 degrees Fahrenheit. Room temperature is typically considered 25 degrees Celsius, which is equal to 77 degrees Fahrenheit.

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3 years ago

The speed of sound in air is approximately 340 m/s. The speed of light in air is approximately 3 x 108 m/s. If 10 seconds elapse

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Answer:

3400 m

Explanation:

Both lightning and thunder happen at the same time but one is faster than the other. The distance traveled by a sound can be calculated from its speed such that;

speed = distance/time, hence, distance = speed x time.

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3 years ago

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What is Restoring force for large waves is A. Wind, B. Capillary Action, C. Diffusion D.Friction, or E. Gravity

jek_recluse [69]

The answer would be c.diffution

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3 years ago

A solid circular plate has a mass of 0.25 kg and a radius of 0.30 m. It starts rolling from rest at the top of a hill 10 m long

KATRIN_1 [288]

To solve the problem it is necessary to apply the equations related to the conservation of both <em>kinetic of rolling objects</em> and potential energy and the moment of inertia.

The net height from the point where it begins to roll with an inclination of 30 degrees would be

$h=Lsin30$

$h=10sin30$

$h=5m$

In the case of Inertia would be given by

$I = \frac{mR^2}{2}$

In general, given an object of mass m, an effective radius k can be defined for an axis through its center of mass, with such a value that its moment of inertia is

$I = mk^2$

$\frac{mR^2}{2}= mk^2$

$\frac{k^2}{R^2}=\frac{1}{2}$

Replacing in Energy conservation Equation we have that

Potential Energy = Kinetic Energy of Rolling Object

$mgh = \frac{1}{2}mv^2(1+\frac{k^2}{r^2})$

$9.8*5=\frac{1}{2}v^2(1+\frac{1}{2})$

$v^2 (1.5) = 98$

$v=8.0829m/s$

Therefore the correct answer is C.

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3 years ago