Answer:
The equation for the distance Jane's trainer bikes is 
.
Step-by-step explanation:
We have attached diagram for your reference.
Given:
Distance traveled on bike towards south = 16 miles
Distance she ran towards west = 12 miles
We need to find distance Jane's trainer bikes.
Solution:
Let the distance Jane's trainer bike be 'x'.
Now we will assume it to be right angled triangle.
So by Pythagoras theorem which states that;
"Square of the third side is equal to the sum of square of the other two sides."
framing in equation form we get;
Hence the equation for the distance Jane's trainer bikes is .
On solving we get;
Hence Jane's trainer bikes a distance of 20 miles.
Answer:
the minimum is (1,-9)
Step-by-step explanation:
y = 5x^2 - 10x - 4
since the parabola opens upward 5>0, this will have a minimum
it will occur along the axis of symmetry h=-b/2a
y =ax^2 +bx+c
h = -(-10)/2*5
h = 10/10 =1
the minimum occurs at x =1
the y value for the minimum is calculated by substituting x =1 back into the equation
y = 5 * 1^2 - 10*1 -4
y = 5*1^2 -10 -4
y = 5-10-4
y = -9
the minimum is (1,-9)
Answer:
which class question is this
That's vertex form for a parabola 
and we read off vertex (p,q) as
Answer: Vertex (5,7)
The negative <em>a</em> tells us this is a downward opening parabola (upside down from the usual 
. I remember CUP - Concave Up Positive; here <em>a </em>is negative so not a cup, instead concave <em>down.</em> The same rule applies to second derivatives in calculus so memorize it now and use it later.
Answer: downward
