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inna [77]
3 years ago
13

What is the the ozone layer​

Physics
2 answers:
Natasha_Volkova [10]3 years ago
5 0

The ozone layer is one layer of the stratosphere, the second layer of the Earth’s atmosphere.

SIZIF [17.4K]3 years ago
4 0
The ozone layer is in space
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Which factors are used to calculate the kinetic energy of an object? Check all that apply.
Verizon [17]
Gravity and velocity
8 0
3 years ago
When a car accelerates from a standing start, the crash test dummy appears to be pressed backward into the seat cushion. Which o
Setler [38]

<u>Answer:</u>

Option: D. Gravity is pulling the crash test dummy in the direction the car is moving.

<u>Explanation: </u>

When a car accelerates from a standing start, the crash test dummy appears to be pressed backward into the seat cushion because the gravity is pulling the crash test dummy in the direction the car is moving.  

Basically when the car is starting, the person inside is in static position and the car is going to move. So it is putting a force on the person to move on the same speed. But as the person is sitting static hence gravity is pulling him behind from moving. Hence, The dummy appears to be pressed backward.

7 0
3 years ago
Will the net force be greater or lesser for objects with greater mass?
Archy [21]
The net force will be lesser for objects with greater mass
6 0
3 years ago
A 562 N trunk is on frictionless plane inclined at 30.0 degrees from the horizontal. What is the acceleration of the trunk down
Len [333]

Answer: 0m/s²

Explanation:

Since the forces acting along the plane are frictional force(Ff) and moving force(Fm), we will take the sum of the forces along the plane

According newton's law of motion

Summation of forces along the plane = mass × acceleration

Frictional force is always acting upwards the plane since the body will always tends to slide downwards on an inclined plane and the moving acts down the plane

Ff = nR where

n is coefficient of friction = tan(theta)

R is normal reaction = Wcos(theta)

Fm = Wsin(theta)

Substituting in the formula of newton's first law we have;

Fm-Ff = ma

Wsin(theta) - nR = ma

Wsin(theta) - n(Wcos(theta)) = ma... 1

Given

W = 562N, theta = 30°, n = tan30°, m = 56.2kg

Substituting in eqn 1,

562sin30° - tan30°(562cos30°) = 56.2a

281 - 281 = 56.2a

0 = 56.2a

a = 0m/s²

This shows that the trunk is not accelerating

4 0
3 years ago
A 1.5kg piece of copper is set out in the sun. Its temperature rises from
Nata [24]

Answer:

<u>8.13 kJ</u>

Explanation:

Q = mCT where Q is the energy (in Joules, here), m is the mass (kg, here) C is the specific heat, and T is the temperature (C).

Q = mCT

Q = (1.5kg)*((387J/(kg*C))*(14C)

Q = 8127 J, or 8.13 kJ with 3 sig figs.

7 0
3 years ago
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