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Archy [21]
2 years ago
12

What is the range of motion of the elbow if extension is 0° and flexion is 145°?

Physics
1 answer:
inna [77]2 years ago
6 0

Answer:

0 to 145 degrees

Explanation:

The normal range of flexion and extension is from 0 to 145 degrees.

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Which of the following is an example of kinetic mechanical energy?
nata0808 [166]

Answer:

A

Explanation:

Kinetic energy must be moving. Potential energy has the ability to move but is not doing so at the moment.

A is likely the answer. But there's lots involved in that kind of motion.

B If the ball is elevated, it implies it is not moving yet. It has potential energy.

C Again, the spring is compressed. It will push something when it moves, but it is not moving yet.

D The load gun's bullet is not moving. It's still potential energy.

E. The mouse trap is set, but it is not moving. When the mouse eats the bait then it's potential energy will transform into kinetic energy.

8 0
3 years ago
A skydiver jumps out of a hovering helicopter. A few seconds later, another diver jumps out, so they both fall along the same ve
Sergio039 [100]

Answer:

distance difference would a) increase

speed difference would f) stay the same

Explanation:

Let t be the time the 2nd skydiver takes to travel, since the first skydiver jumped first, his time would be t + Δt where Δt represent the duration between the the first skydiver and the 2nd one. Remember that as t progress (increases), Δt remain constant.

Their equations of motion for distance and velocities are

s_2 = gt^2/2

s_1 = g(t + \Delta t)^2/2

v_2 = gt

v_1 = g(t + \Delta t)

Their difference in distance are therefore:

\Delta s = s_1 - s_2 = g(t + \Delta t)^2/2 - gt^2/2

\Delta s = g/2((t + \Delta t)^2 - t^2)

\Delta s = g/2(t + \Delta t - t)(t + \Delta t + t) (AsA^2 - B^2 = (A-B)(A+B)

\Delta s = g\Delta t/2(2t + \Delta t)

So as time progress t increases, Δs would also increases, their distance becomes wider with time.

Similarly for their velocity difference

\Delta v = v_1 - v_2 = g(t + \Delta t) - gt

\Delta v = gt + g\Delta t - gt = g\Delta t

Since g and Δt both are constant, Δv would also remain constant, their difference in velocity remain the same.

This of this in this way: only the DIFFERENCE in speed stay the same, their own individual speed increases at same rate (due to same acceleration g). But the first skydiver is already at a faster speed (because he jumped first) when the 2nd one jumps. The 1st one would travel more distance compare to the 2nd one in a unit of time.

8 0
3 years ago
Read 2 more answers
Show that the entire Paschen series is in the infrared part of the spectrum. To do this, you only need to calculate the shortest
mr_godi [17]

Answer and Explanation:

The computation of the shortest wavelength in the series is shown below:-

\frac{1}{\lambda} = R(\frac{1}{n_f^2} - \frac{1}{n_i^2} )

Where

\lambda represents wavelength

R represents Rydberg's constant

n_f represents Final energy states

and n_i represents initial energy states

Now Substitute is

1.097\times 10^7\ m^{-1}\ for\ R, \infty for\ n_i,\ 3 for\ n_i,\\\\\ \frac{1}{\lambda} = R(\frac{1}{n_f^2} - \frac{1}{n_i^2} )

now we will put the values into the above formula

= 1.097\times 10^7 m^{-1}(\frac{1}{3^2} - \frac{1}{\infty^2} )\\\\ = 1.097\times10^7\ m^{-1} (\frac{1}{9} )

= 1218888.889 m^{-1}

Now we will rewrite the answer in the term of \lambda

\lambda = \frac{1}{1218888.889} m\\\\ = 0.82\times 10^{-6} m

So, the whole Paschen series is in the part of the spectrum.

8 0
4 years ago
The plug has a diameter of 30 mm and fits within a rigid sleeve having an inner diameter of 32 mm. Both the plug and the sleeve
Katena32 [7]

Answer:

P=740 KPa

Δ=7.4 mm

Explanation:

Given that

Diameter of plunger,d=30 mm

Diameter of sleeve ,D=32 mm

Length .L=50 mm

E= 5 MPa

n=0.45

As we know that

Lateral strain

\varepsilon _t=\dfrac{D-d}{d}

\varepsilon _t=\dfrac{32-30}{30}

\varepsilon _t=0.0667

We know that

n=-\dfrac{\epsilon _t}{\varepsilon _{long}}

\varepsilon _{long}=-\dfrac{\epsilon _t}{n}

\varepsilon _{long}=-\dfrac{0.0667}{0.45}

\varepsilon _{long}=-0.148

So the axial pressure

P=E\times \varepsilon _{long}

P=5\times 0.148

P=740 KPa

The movement in the sleeve

\Delta =\varepsilon _{long}\times L

\Delta =0.148\times 50

Δ=7.4 mm

6 0
3 years ago
Energy is defined as
vodka [1.7K]
I believe that your answer is going to be C. The ability to do work
3 0
3 years ago
Read 2 more answers
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