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Archy [21]
2 years ago
12

What is the range of motion of the elbow if extension is 0° and flexion is 145°?

Physics
1 answer:
inna [77]2 years ago
6 0

Answer:

0 to 145 degrees

Explanation:

The normal range of flexion and extension is from 0 to 145 degrees.

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A polonium isotope with an atomic mass of 211.988868 u undergoes alpha decay, resulting in a daughter isotope with an atomic mas
prisoha [69]

Answer:

 K = 9.53 MeV

Explanation:

The kinetic energy that the alpha particle has emitted, is the energy in excess after removing the resting energy of the atoms and the helium nucleus that forms the alpha particle

Since energy and masses are related and cannot be

          m₀ c² = m_{f} c² + m_He c²+ K

          K = c² (m₀ - m_{f} - m_He)

           

the mass of the Helium atom is 4 u

           K = (3 10⁸)² (211,988868 -207.976652 - 4,002) 1,661 10⁻²⁷

           K = 14,949 10⁻¹¹ (0.0102)

             

          K = 1,527 10⁻¹² J

let's reduce 1 J = 6,242 10¹² MeV

           K = 9.53 MeV

7 0
3 years ago
In February 1955, a paratrooper fell 362 m from an airplane without being able to open his chute but happened to land in snow, s
serious [3.7K]

Answer:

s = 0.9689 m

Explanation:

given,

Height of fall of paratroopers = 362 m

speed of impact = 52 m/s

mass of paratrooper = 86 Kg

From from snow on him = 1.2 ✕ 10⁵ N

now using formula

F = m a

a = F/m

a = \dfrac{1.2 \times 10^5}{86}

a =1395.35\ m/s^2

Using equation of motion

v² = u² + 2 a s

s =\dfrac{v^2}{2a}

s =\dfrac{52^2}{2\times 1395.35}

s = 0.9689 m

The minimum depth of snow that would have stooped him is  s = 0.9689 m

8 0
3 years ago
Consider a piston filled with 3 mols of an ideal gas, kept at a constant temperature 290 K. We slowly compress the gas starting
kap26 [50]

Answer: -5013.65\ J

Explanation:

Given

No of moles n=3

Temperature T=290\ K

Initial volume V_1=2\ m^3

Final volume V_2=1\ m^3

Work done in constant temperature process is

W=nRT\ln \left(\dfrac{V_2}{V_1}\right)

Insert the values

\Rightarrow W=3\times 8.314\times 290\ln \left (\dfrac{1}{2}\right)\\\\\Rightarrow W=-870\times 8.314\times \ln (2)\\\Rightarrow W=-5013.65\ J

5 0
3 years ago
Which statements about tornadoes are true? Check all that apply.
fgiga [73]

Answer:

The answer is B,C,D

Explanation:

I took the test

8 0
3 years ago
Read 2 more answers
The Pacific Giant Kelp grows at a rate of 18 in/day. How many centimeters per hour is this?
Airida [17]

For this case we must do a conversion. By definition we have to:

1 inch equals 2.54 centimeters

1 day equals 24 hours.

So, we have:18 \frac {in} {day} * \frac {1} {24} \frac {day} {h} * \frac {2.54} {1} \frac {cm} {in} =

Canceling units we have:

\frac {18 * 1 * 2.54} {24 * 1} \frac {cm} {h} =\\\frac {45.72} {24}\frac {cm} {h} =

1,905 \frac {cm} {h}

Answer:

1,905 \frac {cm} {h}

5 0
3 years ago
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