What is the range of motion of the elbow if extension is 0° and flexion is 145°?
1 answer:
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Here the block has two work done on it
1. Work done by gravity
2. Work done by friction force
So here it start from height "h" and then again raise to height hA after compressing the spring
So work done by the gravity is given as
Now work done by the friction force is to be calculated by finding total path length because friction force is a non conservative force and its work depends on total path
Total work done on it
So answer will be
None of these