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3 years ago

8

Given that tan0= -1, what is the value of sec0, for 3pi/2<0<2pi?

2 answers:

Maru [420]3 years ago

7 0

Answer: Choice B. sqrt(2)

Draw out a right triangle in quadrant IV as you see in the attached image below. The horizontal and vertical legs are both 1 unit long. To ensure that the signs are properly set up, I am making the vertical leg BC have a label "-1" to mean this is below the x axis. Note how

tan(theta) = opposite/adjacent = BC/AB = -1/1 = -1

Use the pythagorean theorem to find that the hypotenuse AC is sqrt(2) units long

a^2 + b^2 = c^2

(1)^2 + (1)^2 = c^2

2 = c^2

c^2 = 2

c = sqrt(2)

The secant of theta is the ratio of the hypotenuse over the adjacent side, so we end up with

sec(theta) = hypotenuse/adjacent

sec(theta) = AC/AB

sec(theta) = sqrt(2)/1

sec(theta) = sqrt(2) which is why choice B is the answer

Eddi Din [679]3 years ago

7 0

Answer:

B. on E2020

Step-by-step explanation:

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An object at the top of a building with height 110 feet is thrown upward with an initial speed of 23 ft/s. Find its position z(t

alina1380 [7]

Answer:

Step-by-step explanation:

Given

Height of building is $h=110\ ft$

Initial upward velocity $u=23\ ft/s$

height of object is given by

$z(t)=ut+\frac{1}{2}gt^2$

but building is already at a height of 110 ft so z(t) must be given by

$Z(t)=ut+\frac{1}{2}(-g)t^2+110$

$Z(t)=23\times t-\frac{1}{2}\times 9.8\times t^2$

$Z(t)=-16t^2+23t+110$

Time when it hits is given by when Z(t)=0[/tex]

$-16t^2+23t+110=0$

$t=\frac{-23\pm \sqrt{(23)^2-4\times (-16)\times 110}}{2\times (-16)}$

$t=\frac{-23\pm 87}{-32}$

$t=3.43\ s$

6 0

4 years ago

Plz help fast!!

Leto [7]

Answer:

D. 16 km

Step-by-step explanation:

Hope this helps!

6 0

3 years ago

If V is the midpoint of and W is the midpoint of , then what is VS?4 units8 units10 units20 units

Bess [88]

Is this on a graph if so you need to explain futher

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3 years ago

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The quotient of two negative integers results in an integer.How does the value of the quotient compare to the value of the origi

Aleksandr-060686 [28]

It is the inverse of the two added together

4 0

3 years ago

Flying against the wind, a jet travels 2190 miles in 3 hours. Flying with the wind, the same jet travels 9520 miles in 8 hours.

dezoksy [38]

Answer:

Velocity of jet in still air is 970 miles per hour and velocity of wind is 210 miles per hour.

Step-by-step explanation:

Jet's velocity against wind is

3040/4 = 760 miles per hour and flying with wind it is

8260/7 = 1180 miles per hour.

Let the velocity of jet in still air be x miles per hour and velocity of wind be y miles per hour.

As such its velocity against wind is x − y and with wind is x + y and therefore

x − y = 760 and x + y = 1180

Adding the two 2 x = 1940 and x = 970 and y = 1180 − 970 = 210

Hence velocity of jet in still air is 970 miles per hour and velocity of wind is

210 miles per hour.

Actual Answer:

https://socratic.org/questions/flying-against-the-wind-a-jet-travels-3040-miles-in-4-hours-flying-with-the-wind

7 0

3 years ago