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3 years ago

Given that tan0= -1, what is the value of sec0, for 3pi/2<0<2pi?

Mathematics

2 answers:

Maru [420]3 years ago

7 0

Answer: Choice B. sqrt(2)

Draw out a right triangle in quadrant IV as you see in the attached image below. The horizontal and vertical legs are both 1 unit long. To ensure that the signs are properly set up, I am making the vertical leg BC have a label "-1" to mean this is below the x axis. Note how

tan(theta) = opposite/adjacent = BC/AB = -1/1 = -1

Use the pythagorean theorem to find that the hypotenuse AC is sqrt(2) units long

a^2 + b^2 = c^2

(1)^2 + (1)^2 = c^2

2 = c^2

c^2 = 2

c = sqrt(2)

The secant of theta is the ratio of the hypotenuse over the adjacent side, so we end up with

sec(theta) = hypotenuse/adjacent

sec(theta) = AC/AB

sec(theta) = sqrt(2)/1

sec(theta) = sqrt(2) which is why choice B is the answer

Eddi Din [679]3 years ago

7 0

Answer:

B. on E2020

Step-by-step explanation:

You might be interested in

If x is a positive integer, for how many different values of x is sqrt48/x a whole number?

slava [35]

Answer:

The only possible values of x that fulfill with both conditions are 3, 12 and 48.

Step-by-step explanation:

1. What are the positive integers? Also know as the whole numbers or the counting numbers. They start from 1, and continue to 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, etc.

2. What are the whole numbers? The definition of whole numbers is that they are the number with no fractions or decimals.

3. According to those definitions, x must be a positive integer and the result of √48/x, must be a whole number.

4. For fulfilling the first condition, x must be only a value from 1 to 48.

5. For fulfilling the second condition, the result of √48/x must be a whole number. It means it must be 1, 2, 3, 4, 5 or 6. From 7 is not possible to continue because those numbers are bigger than 48, for example √49, √64, √81, √100 and so on, and it would be impossible to fulfill with the first condition.

6. So, we have just 6 possible options (√48/x = 1, √48/x = 2, √48/x = 3, √48/x = 4, √48/x = 5 and √48/x =6). Let's review in detail one by one.

√48/x = 1, Is there any value of x for fulfilling both conditions? Yes, it's. It's 48. 

√48/x = 1 and let's replace x by 48.

√48/48 = √1 = 1

√48/x = 2, Is there any value of x for fulfilling both conditions? Yes, it's. It's 12. 

√48/x = 2 and let's replace x by 12.

√48/12 = √4 = 2

√48/x = 3, Is there any value of x for fulfilling both conditions? No, it isn't.

There isn't any whole number that allow us to fulfill with this: √48/x = √9 = 3

√48/x = 4, Is there any value of x for fulfilling both conditions? Yes, it's. It's 3.

√48/x = 4 and let's replace x by 3.

√48/3 = √16 = 4

√48/x = 5 Is there any value of x for fulfilling both conditions? No, it isn't.

There isn't any whole number that allow us to fulfill with this: √48/x = √25 = 5

√48/x =6 Is there any value of x for fulfilling both conditions? No, it isn't.

There isn't any whole number that allow us to fulfill with this: √48/x = √36 = 6.

The only possible values of x that fulfill with both conditions are 3, 12 and 48.

6 0

3 years ago

The difference of a number and 5 is 7 less than the product of 3 and a number

IrinaK [193]

$x - 5 = 3x - 7$

$x + 2 = 3x$

$2x = 2$

$x = 1$

4 0

3 years ago

MAX POINTS PLS ANSWER CORRECTLY OR WILL REPORT ty !

Oksana_A [137]

Answer:

136112 $cm^{2}$

Step-by-step explanation:

since the outer circle is 25cm wider on one side, the radius of outer circle is 25 cm wider. (imagine rotating the green line to match with the pink line, you'll see the outer circle radius more clearly)

r of inside circle = 148.4/2 = 74.2

r of outside circle = 74.2 +25 = 99.2

the shaded region = A of outer circle - A of inner circle

=3.14(99.2)^2 - 3.14(74.2)^2

area of a circle is $\pi r^{2}$ , I plugged in known values above^.