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Dovator [93]
3 years ago
6

How to find the multiplicity of a zero of a polynomial function?

Mathematics
1 answer:
Monica [59]3 years ago
3 0
<span>The multiplicity of a zero of a polynomial function is how many times a particular number is a zero for a given polynomial.

For example, in the polynomial function f(x)=x(x+4)^2(x-2)^3, the zeros are 0 with a multiplicity of 1, -4 with a multiplicity of 2, and 2 with a multiplicity of 3.

Although this polynomial has only three zeros, we say that it has six zeros (or degree of 6) counting the <span>multiplicities.</span></span>
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Simplified product ?
mel-nik [20]

Answer:

Last choice is correct.

Step-by-step explanation:

\left(\sqrt{10x^4}-x\sqrt{5x^2}\right)\left(2\sqrt{15x^4}+\sqrt{3x^3}\right)

\left(x^2\sqrt{10}-x\cdot x\sqrt{5}\right)\left(2\cdot x^2\sqrt{15}+x\sqrt{3x}\right)

\left(x^2\sqrt{10}-x^2\sqrt{5}\right)\left(2x^2\sqrt{15}+x\sqrt{3x}\right)

x^2\sqrt{10}\left(2x^2\sqrt{15}+x\sqrt{3x}\right)-x^2\sqrt{5}\left(2x^2\sqrt{15}+x\sqrt{3x}\right)

2x^4\sqrt{150}+x^3\sqrt{30x}-2\sqrt{75}x^4-x^3\sqrt{15x}

2x^4\cdot5\sqrt{6}+x^3\sqrt{30x}-2\cdot5\sqrt{3}x^4-x^3\sqrt{15x}

10x^4\sqrt{6}+x^3\sqrt{30x}-10\sqrt{3}x^4-x^3\sqrt{15x}

10x^4\sqrt{6}+x^3\sqrt{30x}-10x^4\sqrt{3}-x^3\sqrt{15x}

Hence final answer is 10x^4\sqrt{6}+x^3\sqrt{30x}-10x^4\sqrt{3}-x^3\sqrt{15x}


5 0
3 years ago
How do you find slope, y- intercept, slope- intercept form, and point slope form for (-10,-17) (-8,-15.7)
krek1111 [17]

Answer:

-10=x1 -17=y1

-8=x2 -15.7=y2

formula:

y2 -y1

_____ =m

x2-x1

y1=m(x1)+b

Step-by-step explanation:


7 0
3 years ago
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Nina [5.8K]

Answer:

Step-by-step explanation:

hearing, taste, touch,

5 0
3 years ago
THIS IS FUNNY
yaroslaw [1]

Answer:

thats funny lol :)

Step-by-step explanation:

8 0
2 years ago
2 lines intersect and create VERTICAL angles. One of the angles measures (3n-28) degrees and the other angle measures 83 degrees
kykrilka [37]

Answer:

n=37

Step-by-step explanation:

Two lines intersect and create vertical angles.

The vertical angles are (3n-28)^\circ$ and 83^\circ.

We know that vertical angles (also called vertically opposite angles) are equal. Therefore:

(3n-28)^\circ$ = 83^\circ.\\3n=28+83\\3n=111\\$Divide both sides by 3\\n=37

8 0
3 years ago
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