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Citrus2011 [14]
3 years ago
10

Ashley is keep track pf the growth of a bamboo plant. When she purchased the plant last month its height was 8.75 inches.its hei

gt today is 9.5 inches. Assuming that the growth rate remains unchanged,which equation models the height of the bamboo plant after x months of growth? Using the graph,estimate the height of the plant in 6 months
Mathematics
2 answers:
sergeinik [125]3 years ago
5 0

Answer:

D) y = .75x + 8.75;about 13.25 inches

Fantom [35]3 years ago
4 0
9.5+(.75 x X)  and in 6 months the bamboo would be 14 inches
hope this helps
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crimeas [40]

Answer:

hope this helps you out good luck with your math

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3 years ago
Solve photo question. Mathematics. Please. Easy one. And last one.
Elan Coil [88]
A collection of nickels and dimes is worth $4.40. There are 53 coins in all. How many nickels are there?

Nickel is a US coin worth 5 cents or 0.05.
Dime is a US coin worth 10 cents or 0.10

n + d = 53
0.05n + 0.10d = 4.40

n = 53 - d
0.05(53 - d) + 0.10d = 4.40  
2.65 - 0.05d + 0.10d = 4.40
0.05d = 4.40 - 2.65
0.05d = 1.75
d = 1.75 / 0.05
d = 35

n = 53 - d
n = 53 - 35
n = 18 

There are 18 nickels and 35 dimes.

0.05n + 0.10d = 4.40
0.05(18) + 0.10(35) = 4.40
0.90 + 3.5 = 4.40
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4 0
3 years ago
Read 2 more answers
A certain dishwasher uses 29 kilowatts of energy per hour.if the dishwasher was used 156 hours last year how many kilowatts of e
hram777 [196]
156 x 29 = 4524 kilowatts of energy
6 0
4 years ago
What is the area of the circle if XY = 5.4 mm? 5.4π mm2 7.29π mm2 10.8π mm2 14.58π mm2
Dafna1 [17]

Answer: 7.29π mm²

Step-by-step explanation:

First, I am assuming XY is the diameter of the circle :)

The formula for the area of a circle is πr² (r = radius)

So that means we need to divide the diameter by 2 to find the radius

5.4 / 2 = 2.7

Now we simply plug in our numbers!

3.14 · 2.7²

3.14 · 7.29

And that's it!

Hope this helped you :)

3 0
4 years ago
Intercepts:
Tema [17]
An x-intercept is the point where the function passes the x axis at y=0.
The y-intercept is the point where the function crosses the y axis at x=0

1. It is an x-intercept, so y = 0. The ordered pair would be (-6, 0)
2. It is a y-intercept, so x = 0. The ordered pair would be (0, -2.3)
3. It is a y-intercept, so x=0. The ordered pair would be (0, 3/4)

To find the x-intercept, set y = 0. To find the y-intercept, set x=0

4. y-intercept: y = 3(0) -9. y = -9 The y-intercept is at (0, -9)
x-intercept: 0 = 3x -9. 9 = 3x. x = 3. The x-intercept is at (3, 0)

5. x intercept: 0 = 5x +10. -10 = 5x. x = -2. The x-intercept is at (-2, 0)
y-intercept: y = 5(0) + 10. y = 10. The y-intercept is at (0, 10)

If you look at finding the y-intercepts in the two problems above, you may see there is a pattern forming. The y-intercept is the number that your adding or subtracting that is located after the x (ex. y = 4x - 2 - the y-intercept would be -2)

9. First, find the x and y-intercepts. The y intercept is -3 You’d graph that at (0, -3). 0 = -1/2x - 3. -1/2x = 3. x = -6 so the x-intercept is at (-6, 0). If you only need to graph 2 points, then you can graph just those two points and draw a line between them.

To graph y=-1/2x + 3, start at the y-intercept and use the slope (-1/2) to find other points. Because your slope is -1/2, you’d go down 1 unit and then to the right 2 units. That would be your next point. If you wanted your line to go further up, go up one unit and then to the left 2 units. That would be your next point.

I am not sure what you need to do on 11 and 12

I think you should try 7, 8 and 10 on your own and let me know if you have any questions on them or if you are stuck on anything.
3 0
3 years ago
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