I think its the second one but just a fyi the site your on is ready and it looks like your doing the major test, not every answer on it are you suppose to get right its a test to see what you know and what you need to know
Answer: The correct option is (A). When the radicand is negative
Step-by-step explanation: We are given to select the correct option by which we can tell that a quadratic equation has no real solutions.
We know that for the quadratic equation
the radicand is given by
Based on the radicand "D", we have the following rules:
(i) If D > 0 (positive), then the two solutions are real and unequal.
(ii) If D = 0, then the two solutions are equal.
(iii) If D< 0 (negative), then the two solutions are complex (not real).
Thus, when the radicand is negative, then the quadratic equation has no real solutions.
Option (A) is correct.
Slope of the line J
(6-1) / (-3-(-6))
5 / 3
so
m = 5/3
If this line passes through (15,-1)
y = mx + c
-1 = (5/3)*15 + c
-1 = 25 + c
c = -26
equation is
y = (5/3)x - 26
Answer:
0.4 or 0.7
Step-by-step explanation: it wouldnt take that long to throw the ball
Answer: 26
Step-by-step explanation: From the remainder theorem ,
If P (x) = 2x⁴ ⁻ x³ + 2x² ⁻ 6. is divided by ( x - 2 ).
It means that if P(x) is divided by (x - 2 ) and leaves a Remainder, it implies that x - 2 is not a factor of P(x) , but if it leaves no remainder, it means x-2 is a factor of P(x).
Therefore , to find the remainder, find the zero of x - 2, and substitutes for the value in P(x) to know the remainder
x - 2 = 0
x = 2
Now put this in P(x)
P(x) = 2(2)⁴ - (2)³ + 2(2)² - 6
= 2(16) -8 + 2(4) -6
= 32 -8 +8 -6
=26
Therefore the remainder when P(x) is divided by x -2
=26
Note: Since the division of P(x) by x - 2 leaves a remainder, it means that
x - 2 ≠ a factor of P(x)
