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Agata [3.3K]
3 years ago
14

Suppose you had to find 4 x 57. How are the expanded algorithm and the standard algorithm alike? And how are they different?

Mathematics
1 answer:
Nookie1986 [14]3 years ago
4 0
The expanded algorithm is given as follows:

4 x 57 = (4 x 50) + (4 x 7) = 200 + 28 = 228


The standard algorithm is given as follows:

\ \ \ \ \ \ {_2}\\{ \ \ \ \ \ \ 5 \ 7} \\ \times \ \ \ \ \ 4 \\ = \overline{\underline{2\ 2\ 8}}
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Find the inverse of g(x) = -2x + 1
Alika [10]

Answer:

g-1(x) = (1 - x)/2.

Step-by-step explanation:

Let y = -2x + 1

y + 2x = 1

2x = 1 - y

x = (1 - y)/2

So the inverse g-1(x) = (1 - x)/2.

8 0
2 years ago
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A shoe store orders shoes from the manufacturer and sells them at a mall. Storing shoes at the store costs $3 per shoe pair for
DerKrebs [107]

Answer:

the function that models the total inventory costs as a function of x is;

$( \frac{112500}{x} + (\frac{3}{2})x )

Step-by-step explanation:

Given the data in the question;

cost of storing the shoes ( Holding cost ) = $ 3 per year

ordering cost ( Co ) fixed = $ 25 per order

cost of each pair = $ 5 per shoe pair

Total demand = 4500 shoe pairs

Total Inventory cost = Holding cost Ordering cost

so

Total Inventory cost = \frac{4500}{x}( $ 25) + \frac{1}{2}× $3 × x

Total Inventory cost = $( \frac{4500*25}{x} + (\frac{3}{2})x )

Total Inventory cost = $( \frac{112500}{x} + (\frac{3}{2})x )

Therefore, the function that models the total inventory costs as a function of x is; $( \frac{112500}{x} + (\frac{3}{2})x )

3 0
3 years ago
Find the zeros of the quadratic function: y=x^2-4x-12
TEA [102]

Answer:

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8 0
2 years ago
In a production process, the probability of manufacturing a defective rear view mirror for a car is 0.075. Assume that the quali
Leviafan [203]

Answer:

The probability that the 3rd defective mirror is the 10th mirror examined = 0.0088

Step-by-step explanation:

Given that:

Probability of manufacturing a defective mirror = 0.075

To find the probability that the 3rd defective mirror is the 10th mirror examined:

Let X be the random variable that follows a negative Binomial expression.

Then;

X \sim  -ve  \ Bin (k = 3 , p = 0.075)\\ \\ P(X=x)= \bigg (^{x-1}_{k-1}\bigg)\times P^k\times (1-P)^{x-k}

= \bigg (^{10-1}_{3-1}\bigg)\times 0.075^3\times (1-0.075)^{10-3}

= \bigg (^9_2\bigg)\times 0.075^3\times (1-0.075)^{7}

= \dfrac{9!}{2!(9-2)!}\times 0.075^3\times (0.925)^{7}

= \dfrac{9*8*7!}{2!(7)!}\times 0.075^3\times (0.925)^{7}

= 0.0087999

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2 years ago
Solve for a 2.5+5a=3a+10.5
Oksi-84 [34.3K]

Answer:

a = 4

Step-by-step explanation:


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3 years ago
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