Find the exact solution to the equation. 320 (1/4 )^ x/4 = 5

1 answer:

vladimir2022 [97]2 years ago

8 0

You have to create and equivalent EXPRESSION in the equation that have equal bases then solve for x
SO THE ANSWER IS 12<span />

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Solve for x<br> pls show work<br> 1/2*(x - -6)= -1

Pavlova-9 [17]

Answer: x = -4

Step-by-step explanation:

1/2 * (x - (-6)) = 1

distribute

1/2x + 3 = 1

isolate the variable

1/2x = -2

x = - 4

5 0

3 years ago

Find the radius of convergence, r, of the series. ∞ xn 2n − 1 n = 1 r = 1 find the interval, i, of convergence of the series. (e

Bingel [31]

Assuming the series is

$\displaystyle\sum_{n\ge1}\frac{x^n}{2n-1}$

The series will converge if

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{x^{n+1}}{2(n+1)-1}}{\frac{x^n}{2n-1}}\right|$

We have

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{x^{n+1}}{2(n+1)-1}}{\frac{x^n}{2n-1}}\right|=|x|\lim_{n\to\infty}\frac{\frac1{2n+1}}{\frac1{2n-1}}=|x|-\lim_{n\to\infty}\frac{2n-1}{2n+1}=|x|$

So the series will certainly converge if $-1$ , but we also need to check the endpoints of the interval.

If $x=1$ , then the series is a scaled harmonic series, which we know diverges.

On the other hand, if $x=-1$ , by the alternating series test we can show that the series converges, since

$\left|\dfrac{(-1)^n}{2n-1}\right|=\dfrac1{2n-1}\to0$

and is strictly decreasing.

So, the interval of convergence for the series is $-1\le x$ .

6 0

3 years ago

Write an algebraic expression for the following

MrRa [10]

Answer:

12t = c

Step-by-step explanation:

I believe that's it

8 0

3 years ago

Read 2 more answers

What is the solution for the system of equations {4x−3y=36x−2y=4?