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Eddi Din [679]
3 years ago
15

Hi uuuuuuuuuuuuuuuuuuuuuuuuuuuuu

Mathematics
2 answers:
Agata [3.3K]3 years ago
7 0

Answer:

hi

Step-by-step explanation:

kaheart [24]3 years ago
3 0

Answer:

???

Step-by-step explanation:

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Find the missing side.<br> Round to the nearest tenth.<br> For all 4 pics
Firlakuza [10]

Answer:

1st pic) 17.8

2nd pic) 16.8

3rd pic) 9.1

4th pic) 13.5

Step-by-step explanation:

<u>1st pic:</u> cos = \frac{adjacent}{hypothenuse}

(write equation) Cos 27 (cos 27 = 0.89) = \frac{x}{20}

(new equation) 0. 89 = \frac{x}{20}

(multiply 20 on both sides) 0.89 x 20 = \frac{x}{20} x 20

(solve) 17.8 = x

<u>2nd pic:</u> tan = \frac{adjacentx}{hypothenuse}

(write equation) tan 40 (tan 40 = 0.84) = \frac{32}{x}

(new equation) 0.84 =  \frac{32}{x}

(multiply 32 on both sides) 0.84 x 20 =  \frac{32}{x} x 20

(solve) 16.8 = x

<u>3rd pic:</u> cos = \frac{adjacent}{hypothenuse}

(write equation) cos 55 (cos 55 = 0.57) = \frac{16}{x}

(new equation) 0.57 = \frac{16}{x}

(multiply 16 on both sides) 0.57 x 16 = \frac{16}{x} x 16

(solve) 9.1 = x

<u>4th pic:</u> tan = \frac{adjacentx}{hypothenuse}

(write eqaution) tan 42 (tan 42 = 0.90) = \frac{x}{15}

(new equation) 0.90 = \frac{x}{15}

(multiply 15 on both sides) 0.90 x 15 = \frac{x}{15} x 15

(solve) 13.5 = x

4 0
3 years ago
Below are the steps to solve an equation:
otez555 [7]

Answer:

x-5=-3

Step-by-step explanation:

|x-5|+2=5

|x-5|=5-2

|x-5|=3

x-5=±3

so x-5=-3 is a correct step.

4 0
3 years ago
Kala, Deandre, and Eric have a total of $119 in their wallets, Kala has $6 more than Deandre. Eric has 3 times what kala has. Ho
Tomtit [17]
Deandre = x
Kala = x + 6
Eric = 3(x+6)
x + x + 6 + 3(x+6) = 119
2x + 6 + 3x + 18 = 119
5x + 24 = 119
5x = 95, x = 19
Deandre has $19
Kala has 19 + 6 = $25
Eric has 3(25) = $75
4 0
3 years ago
What I do by step <br><br> Simplify
ch4aika [34]
Multiply everything by 2 then combine like terms
4 0
3 years ago
What is the area of rectangle ABCD?
lina2011 [118]
Multiply the length by the width and your answer will be there.
8 0
3 years ago
Read 2 more answers
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