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Mars2501 [29]
2 years ago
6

Which statement best describes the process that the diagrams show?

Chemistry
2 answers:
TEA [102]2 years ago
7 0

B. This looks like ice turning to water then to steam

Vika [28.1K]2 years ago
5 0

Answer is: B.) A solid gains kinetic energy to become a liquid and then becomes a gas.

Stage 2 is melting (from solid to liquid) and Stage 2 is boiling (from liquid to gas).

In solid, molecules are closely packed, stiff and do not changes of shape or volume. Solid object does not take on the shape of its container.

Liquids have definite volume, but no fixed shape.

Gases not have definite volume and fixed shape, it depends on its container.

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Identify all of the electrophilic centers in (r)-(−)-carvone below. select all that apply.
drek231 [11]
)-(−)-Carvone is responsible for the characteristic
minty odor and flavor of spearmint oil, and it can also serve as a
useful chiral starting material for organic synthesis. A
carbon-carbon π bond is normally nucleophilic, but one of the two
carbon-carbon π bonds in (R)-(−)-carvone is actually
electrophilic!



Draw resonance structures of (R)-(−)-carvone.
Do not draw resonance and curved arrows in your answer. Include
formal charges and lone pais in yo

4 0
3 years ago
What can cause heat exhaustion?
stepladder [879]

Answer:

i think exposure to cold

8 0
2 years ago
The Haber Process is the main industrial procedure to produce ammonia. The reaction combines nitrogen from air with hydrogen mai
Firdavs [7]

Answer:

A) N_2(g)+3H_2(g)\rightleftharpoons 2NH_3(g).

B) Kc=0.0933.

C) 0.9 mol.

D) Increasing both temperature and pressure.

Explanation:

Hello,

In this case, given the information, we proceed as follows:

A)

N_2(g)+3H_2(g)\rightleftharpoons 2NH_3(g)

B) For the calculation of Kc, we rate the equilibrium expression:

Kc=\frac{[NH_3]^2}{[N_2][H_2]^3}

Next, since at equilibrium the concentration of ammonia is 0.6 M (0.9 mol in 1.5 dm³ or L), in terms of the reaction extent x, we have:

[NH_3]=0.6M=2*x

x=\frac{0.6M}{2}=0.3M

Next, the concentrations of nitrogen and hydrogen at equilibrium are:

[N_2]=\frac{1.5mol}{1.5L}-x=1M-0.3M=0.7M

[H_2]=\frac{4mol}{1.5L}-3*x=2.67M-0.9M=1.77M

Therefore, the equilibrium constant is:

Kc=\frac{(0.6M)^2}{(0.7M)*(1.77M)^3}\\ \\Kc=0.0933

C) In this case, the equilibrium yield of ammonia is clearly 0.9 mol since is the yielded amount once equilibrium is established.

D) Here, since the reaction is endothermic (positive enthalpy change), one way to increase the yield of ammonia is increasing the temperature since heat is reactant for endothermic reactions. Moreover, since this reaction has less moles at the products, another way to increase the yield is increasing the pressure since when pressure is increased the side with fewer moles is favored.

Best regards.

7 0
3 years ago
In a given chemical reaction the energy of products is great than the energy of the reactants which statement is true? (Hint wha
professor190 [17]
The true statement is (A) energy is absorbed during the reaction
For the products to have more energy, they must absorb it from the surrounding.
6 0
3 years ago
How does melting order relate to melting point?
KatRina [158]

Answer:

I think A.

Explanation:I say A because of the substance melting the quicking does have the highest melting point because its the highest.

5 0
2 years ago
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