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SCORPION-xisa [38]
3 years ago
7

Student 1You are supplied with a 100 mL beaker that you weigh on a pocket balance – its weight clean and dry is 29.3 g. You then

dispense 15.0 mL of a clear unknown liquid from a graduated cylinder into the 100 mL beaker. The beaker plus liquid now weighs 44.2 g. Calculate the density of the liquid on the sheet supplied with your data sheets.
Chemistry
1 answer:
navik [9.2K]3 years ago
6 0

Answer:

The answer to your question is: density = 0.993 g/ml

Explanation:

Data

mass beaker empty = 29.3 g

volume of liquid = 15 ml

mass beaker + liquid = 44.2 g

Formula

             density = mass / volume

Process

mass of liquid = 44.2 - 29.3

                       = 14.9 g

             density = 14.9 / 15

                          = 0.993 g/ml

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Four gases were combined in a gas cylinder with these partial pressures: 3.5 atm N2, 2.8 atm O2, 0.25 atm Ar, and 0.15 atm He.
Goryan [66]

Answer:

This can be solved using Dalton's Law of Partial pressures. This law states that the total pressure exerted by a gas mixture is equal to the sum of the partial pressure of each gas in the mixture as if it exist alone in a container. In order to solve, we need the partial pressures of the gases given. Calculations are as follows:

Explanation:

P = 3.00 atm + 2.80 atm + 0.25 atm + 0.15 atm

P = 6.8 atm

3.5 atm = x (6.8 atm)

x = 0.51

8 0
3 years ago
Read 2 more answers
If a buffer solution is 0.220 M in a weak acid ( Ka=7.4×10−5) and 0.540 M in its conjugate base, what is the pH?
valkas [14]

Answer: the pH of the solution is 4.52

Explanation:

Consider the weak acid as Ha, it is dissociated as expressed below

HA     H⁺  +  A⁻

the Henderson -Haselbach equation can be expressed as;

pH = pKa + log( [A⁻] / [HA])

the weak acid is dissociated into H⁺ and A⁻ ions in the solution.

now the conjugate base of the weak acid HA is

HA(aq) {weak acid}     H⁺(aq)  +  A⁻(aq) {conjugate base}

so now we calculate the value of Kₐ as well as pH value by substituting the values of the concentrations into the equation;

pKₐ = -logKₐ

pKₐ = -log ( 7.4×10⁻⁵ )

pKₐ = 4.13

now thw pH is

pH = pKₐ  + log( [A⁻] / [HA])

pH = 4.13 + log( [0.540] / [0.220])

pH = 4.13 + 0.3899

pH = 4.5199 = 4.52

Therefore the pH of the solution is 4.52

6 0
3 years ago
In the following equation, which element has been reduced?
Mila [183]
The answer is A. you sre correct!
4 0
3 years ago
Score! You manage to find a bottle of bromothymol blue and a few extra beakers. You take one of the empty beakers and add some o
mamaluj [8]

Answer:

You manage to find a bottle of bromothymol blue and a few extra beakers. You take one of the empty beakers and add some of the first unlabeled solution and some indicator.

The color changes to yellow.

You then add some solution from the other unlabeled flask into this beaker and see the color change to blue.

What are the identities of each unlabeled solution?

Explanation:

Bromothymol blue is a dye and it is used as an indicator.

It is used as a pH indicator.

In acids, it becomes yellow n in color.

In bases, it turns blue.

You take one of the empty beakers and add some of the first unlabeled solution and some indicator. The color changes to yellow.

That means the unlabeled solution is an acid.

You then add some solution from the other unlabeled flask into this beaker and see the color change to blue.

It is a basic solution.

6 0
2 years ago
In general the state of matter with the most energy is ?
CaHeK987 [17]

<u>Gas</u>

<em>Gas</em><em> </em><em>particles</em><em> </em><em>got</em><em> </em><em>the</em><em> </em><em>most</em><em> </em><em>energy</em><em> </em><em>because of how freely the molecules move</em>

Hope this helped you, have a good day bro cya)

8 0
3 years ago
Read 2 more answers
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