Answer is: Ksp for strontium arsenate is 2.69·10⁻¹⁸.
Balanced chemical reaction (dissociation):
Sr₃(AsO₄)₂(s) → 3Sr²⁺(aq) + AsO₄³⁻(aq).
s(Sr₃(AsO₄)₂) = 0.0650 g/L.
s(Sr₃(AsO₄)₂) = 0.0650 g/L ÷ 540.7 g/mol = 1.2·10⁻⁴ mol/L.
s(Sr²⁺) = 3s(Sr₃(AsO₄)₂).
s(AsO₄³⁻) = 2s(Sr₃(AsO₄)₂).
Ksp = s(Sr²⁺)³ · s(AsO₄³⁻)².
Ksp = (3s)³ · (2s)².
Ksp = 108s⁵.
Ksp = 108 · (1.2·10⁻⁴ mol/L)⁵ = 2.69·10⁻¹⁸.

3 0

3 years ago

Prob.: Consider the combustion of butane (C4H10):

never [62]

<u>Answer:</u> The moles of carbon dioxide formed in the reaction is 20 moles.

<u>Explanation:</u>

We are given:

Number of moles of butane = 5.0 moles

The chemical reaction for the combustion of butane follows the equation:

$2C_4H_{10}(g)+13O_2(g)\rightarrow 8CO_2(g)+10H_2O(l)$

As, oxygen is present in excess. So, it is considered as an excess reagent.

Thus, butane is considered as a limiting reagent because it limits the formation of products.

By stoichiometry of the reaction:

2 moles of butane produces 8 moles of carbon dioxide.

So, 5 moles of butane will produce = $\frac{8}{2}\times 5=20mol$ of carbon dioxide.

Hence, the moles of carbon dioxide formed in the reaction is 20 moles.

7 0

3 years ago

How many molecules are in 3 moles of CO2?

Alenkinab [10]

Answer:

Explanation:

The number of molecules can be found by using the formula

N = n × L

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

N = 3 × 6.02 × 10²³

We have the final answer as

Hope this helps you

3 0

3 years ago

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