Answer with explanation:
The given differential equation is
y" -y'+y=2 sin 3x------(1)
Let, y'=z
y"=z'

Substituting the value of , y, y' and y" in equation (1)
z'-z+zx=2 sin 3 x
z'+z(x-1)=2 sin 3 x-----------(1)
This is a type of linear differential equation.
Integrating factor

Multiplying both sides of equation (1) by integrating factor and integrating we get


Solve the equation for y
x-3y= -18
-3y = -18-x
now, divide both sides with -3
y = (-18-x)/-3
y = 6 +x/3
your slope is 1/3
and y-intercept is 6
1 pound = 16 ounces
20 pounds = 320 ounces
320 ounces + 7 ounces = 327 ounces