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4 years ago

Which scientist is BEST known for research that led to the modern understanding

Physics

1 answer:

pogonyaev4 years ago

4 0

Dalton is best known for research that led to the modern understanding of the atom.

Explanation:

John Dalton is recognised as father of atomic theory. This is because, he was the first researcher to postulate the basic property or a basic model of an atom. He used this postulates for his research in chemistry. Though most of the postulates he stated seemed to be modified in this era. But the concept of a tiny indivisible particle was introduced by him which lead to the research field of atomic particles. Though now they are not indivisible particles any more but still the recognition is given to him for opening a new stream of research. Thus, Dalton is best known for research that led to the modern understanding of the atom.

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Based on Dalton’s law of partial pressures if I have 1 L sample of helium at standard temperature has pressure has a volume of 2

sammy [17]

Answer:

wat?.... anyways if 2 + 2 is 4 then what is 10 x 3974793 ?

Explanation:

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2 years ago

An instructor’s laser pointer produces a beam of light with a circular cross section of diameter 0.900 mm and a total power outp

il63 [147K]

Answer:

$E_0 = 2180.53N/C.$

$B_0 = 7.27*10^{-6}T.$

$U_{avg} = 4.2*10^{-5}J/m^3.$

Explanation:

The Intensity $I$ of the beam is

$I = P /A$

The diameter of the beam is 0.900mm; therefore, the area is

$A = \pi( \dfrac{0.900*10^{-3}}{2} )^2$

$A = 6.36*10^{-7}m^2$

and since $P = 4.00*10^{-3}W$ , the intensity of the beam is

$I = \dfrac{4.00*10^{-3}W}{6.36*10^{-7}m^2}$

$\boxed{I = 6289.3W/m^2.}$

Now, the intensity $I$ is related to $E_0$ by the relation

$I = \dfrac{E_0^2}{2\mu_0 c}$

solving for $E_0$ we get

$E_0 = \sqrt{2\mu_0 c I}$

putting in the numbers we get:

$E_0 = \sqrt{2(1.26*10^{-6}) (3*10^8) (6289.3)}$

$\boxed{E_0 = 2180.53N/C.}$

The amplitude of magnetic field $B_0$ is related to $E_0$ by

$B_0 = \dfrac{E_0}{c}$

putting in numerical values we get:

$B_0 = \dfrac{2180.53}{3*10^8}$

$\boxed{B_0 = 7.27*10^{-6}T. }$

The average energy density of the laser light is

$U_{avg} = \epsilon_0 E_0^2$

$U_{avg} = (8.85*10^{-12}) (2180.53)^2$

$\boxed{U_{avg} = 4.2*10^{-5}J/m^3.}$

8 0

4 years ago

What does N.W.A means?

MissTica

Answer: Well N.W.A is a hip hop group that started back in the late 1900s back then they where pretty cool and fun to listen too well there music was about how life was when they where young well thats all i can say unless you talking about something different.

Explanation:

3 0

4 years ago

The branch of science concerning heat flow and energy conversions is called _____. chemistry thermodynamics conversion science a

tatiyna

The branch of science concerning heat flow and energy conversions is called thermodynamics. The pattern that takes place in the ecosystem regarding the flow of energy is from a higher energy state t a lower energy state. It follows the second law of thermodynamics, the entropy in which all things go into the chaotic state from a higher form into lower form.

5 0

3 years ago

Read 2 more answers

. Boxes are sitting on a conveyor belt as the conveyor is turned on, moving the boxes toward the right. The belt reaches full sp

oksian1 [2.3K]

Answer:

The acceleration of the boxes is 1.5 ft/s²

The displacement of the boxes during the speed-up period is 0.1875 ft.

Explanation:

Hi there!

Let´s convert the 45 ft/min into ft/s:

45 ft/min · 1 min/ 60 s = 0.75 ft/s

It takes the belt 0.5 s to reach this speed. Then, the acceleration of the boxes will be:

a = v/t

Where:

a = acceleration.

v = velocity.

t = time.

a = 0.75 ft/s / 0.5 s

a = 1.5 ft/s²

The acceleration of the boxes is 1.5 ft/s²

The equation of displacement is the following:

x = x0 + v0 · t + 1/2 · a · t²

Where:

x = position of the boxes at time t.

x0 = initial position.

v0 = initial velocity.

t = time.

a = acceleration.

Since the origin of the frame of reference is located at the point where the boxes begin to move, x0 = 0. Since the boxes were initially at rest, v0 = 0. Then:

x = 1/2 · a · t²

x = 1/2 · 1.5 ft/s² · (0.5 s)²

x = 0. 1875 ft

The displacement of the boxes during the speed-up period is 0.1875 ft.

5 0

3 years ago