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kykrilka [37]
2 years ago
15

In real number multiplication, if uv1=uv2 and u does not equal zero we can cancel out u and conclude that v1=v2. Does the same r

ule hold for the dot product?
Physics
1 answer:
Leya [2.2K]2 years ago
6 0

The conclusion v₁=v₂ can not be made. Let u=(1,1,1),v₁=(2,3,-5),v₂=(4,-1,-3). The dot product of u.v₁=uv₂ is satisfied,but v₁≠v₂.The correct answer is c.

<h3>What is dot product?</h3>

The dot product, also known as the scalar product, is an algebraic operation that yields a single integer from two equal-length sequences of numbers.

The dot product of two vectors' Cartesian coordinates is commonly used in Euclidean geometry.

Because there may be more than the 1 vectors satisfying the expression.

\rm uv_1  = 1 \times 2 +1 \times 3 +1 \times(-5)=0

\rm uv_2= 4-1-3 =0

The v₁ is not found equal to the v₂.

The conclusion v₁=v₂ can not be made. Let u=(1,1,1),v₁=(2,3,-5),v₂=(4,-1,-3). The dot product of u.v₁=uv₂ is satisfied,but v₁≠v₂.The correct answer is c.

Hence, the correct answer is c.

To learn more about the dot product, refer to the link;

brainly.com/question/26550859

#SPJ4

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An uncharged capacitor is connected to a 21-V battery until it is fully charged, after which it is disconnected from the battery
attashe74 [19]

Answer:

The voltage bewtween the plates will be 9.5V

Explanation:

Facts:

The capacitance of a parallel plate capacitor having plate area A and plate separation d is C=ϵ0A/d.  

Where ϵ0 is the permittivity of free space.  

A capacitor filled with dielectric slab of dielectric constant K, will have a new capacitance C1=ϵ0kA/d

        C1=K(ϵ0A/d)

        C1=KC   ----------- 1

Where C is the capacitance with no dielectric and C1 is the capacitance with dielectric.

The new capacitance is k times the capacitance of the capacitor without dielectric slab.  

This implies that the charge storing capacity of a capacitor increases k times that of the capacitor without dielectric slab.

Given points

• The terminal voltage of the battery to which the capacitor is connected to charge V=25V

• A dielectric slab of paraffin of dielectric constant K=2  is inserted in the space between the capacitor plates after the fully charged capacitor is disconnected

The charge stored in the original capacitor Q=CV

The charge stored in the original capacitor after inserting dielectric Q1=C1V1

The law of conservation of energy states that the energy stored is constant:

i.e Charge stored in the original capacitor is same as charge stored after the dielectric is inserted.

Q   =  Q1

CV = C1V1

  CV = C1V1  -------2

We derived C1=KC from equation 1. Inserting this into equation 2

   CV = KCV1

 V1 = (CV)/KC

         V/K

       = 21/2.2

      = 9.5

4 0
3 years ago
Please help I’ll give brainliest
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I think the answer is B
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<span> Remember- high energy = short wavelength. </span>
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Read 2 more answers
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Norma-Jean [14]
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