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kykrilka [37]
2 years ago
15

In real number multiplication, if uv1=uv2 and u does not equal zero we can cancel out u and conclude that v1=v2. Does the same r

ule hold for the dot product?
Physics
1 answer:
Leya [2.2K]2 years ago
6 0

The conclusion v₁=v₂ can not be made. Let u=(1,1,1),v₁=(2,3,-5),v₂=(4,-1,-3). The dot product of u.v₁=uv₂ is satisfied,but v₁≠v₂.The correct answer is c.

<h3>What is dot product?</h3>

The dot product, also known as the scalar product, is an algebraic operation that yields a single integer from two equal-length sequences of numbers.

The dot product of two vectors' Cartesian coordinates is commonly used in Euclidean geometry.

Because there may be more than the 1 vectors satisfying the expression.

\rm uv_1  = 1 \times 2 +1 \times 3 +1 \times(-5)=0

\rm uv_2= 4-1-3 =0

The v₁ is not found equal to the v₂.

The conclusion v₁=v₂ can not be made. Let u=(1,1,1),v₁=(2,3,-5),v₂=(4,-1,-3). The dot product of u.v₁=uv₂ is satisfied,but v₁≠v₂.The correct answer is c.

Hence, the correct answer is c.

To learn more about the dot product, refer to the link;

brainly.com/question/26550859

#SPJ4

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3 0
3 years ago
A thread is being pulled off a spool at the rate of 57.3 cm per sec. Find the radius of the spool if it makes 141 revolutions pe
oksano4ka [1.4K]

Answer: r= 0.04meter

Explanation:

The velocity V and angular speed w is related to the radio by

V=w*r

r=V/w

But the standard unit for velocity is m/s so we convert 57.3cm/sec to m/s

57.3/100= 0.57m/s

Also Angular speed w is rad/secs

So we convert rev/min to rad/sec

0.1rad/sec equals 1 rev/mins

141rev/mins * 0.1rad/secs

=14.1rad/sec

r = V/w

= 0.573/14.1

= 0.04m to 2d.p

4 0
4 years ago
Suppose you display a 1 kHz, 2 V sine wave in channel A and a DC, 1V signal in channel B with sensitivities set on 1V/div. You s
defon

Answer:

You are going to see the AC functions shifted down

Explanation:

Because you had a positive DC signal first, you had to readjust the position to the middle, otherwise, the sum of AC and DC would have been shifted up; because of this, your cursor has been moved down and ones the DC disappears from channel B the signal will be shifted down.

Note: Changing from DC to AC in channel B will kill all the DC signal

5 0
3 years ago
Point charges q1 and q2 are separated by a distance of 60 cm along a horizontal axis.
amm1812

Answer:

38 cm from q1(right)

Explanation:

Given, q1 = 3q2 , r = 60cm = 0.6 m

Let that point be situated at a distance of 'x' m from q1.

Electric field must be same from both sides to be in equilibrium(where EF is 0).

=> k q1/x² = k q2/(0.6 - x)²

=> q1(0.6 - x)² = q2(x)²

=> 3q2(0.6 - x)² = q2(x)²

=> 3(0.6 - x)² = x²

=> √3(0.6 - x) = ± x

=> 0.6√3 = x(1 + √3)

=> 1.03/2.73 = x

≈ 0.38 m = 38 cm = x

8 0
3 years ago
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