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romanna [79]
3 years ago
6

Two objects attract each other with a gravitational force of magnitude 9.20×10^-9 N when separated by 19.2 cm. If the total mass

of the objects is 5.01 kg, what is the mass of each?
Physics
1 answer:
melamori03 [73]3 years ago
8 0
The gravitational force between two objects may be calculated by the equation,
                                      F = G x (m1 x m2) / d²
where G is universal gravitational constant, m1 and m2 are the masses of two bodies and  d is the distance between them. Substituting the known values,
                      9.20 x 10^-9 = (6.673 x 10^-11) (5.01 kg x m2) / (0.192m)²
The value of m2 is approximately 1.01 kg.
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LiRa [457]

The object is called a meteor because it is producing Streak of light  and has not yet struck earth.

<h3><u>Explanation:</u></h3>

A meteoroid is a celestial object which is very smaller than an asteroid. These objects are produced as a collision impact from mars or moon and float freely in space without any specific orbit. When they come inside the Earth's gravitational field, they are attracted by the Earth's gravity to Earth's crust. These objects in Earth's atmosphere are called meteors. As they travel through Earth's atmosphere, they do face a huge friction from Earth's atmosphere which let them burn and that is visible as the tail of the meteor.

Most of them are so small that they are burnt away in the atmosphere. But some are bigger and they reach the Earth's surface and are called as meteorites.

4 0
3 years ago
Read 2 more answers
A satellite is launched to orbit the Earth at an altitude of 2.90 x10^7 m for use in the Global Positioning System (GPS). Take t
marin [14]

Answer:

T=66262.4s

Explanation:

From the question we are told that:

Altitude A=2.90 *10^7

Mass m=5.97 * 10^{24} kg

Radius r=6.38 *10^6 m.

Generally the equation for Satellite Speed is mathematically given by

V=(\frac{GM}{d} )^{0.5}

V=(\frac{6.67*10^{-11}*5.97 * 10^{24}}{6.38 *10^6+2.90 *10^7} )^{0.5}

V=3354.83m/s

Therefore

Period T is Given as

T=\frac{2 \pi *a}{V}

T=\frac{2 \pi *(6.38 *10^6+2.90 *10^7}{3354.83}

T=66262.4s

4 0
2 years ago
A jet travels 1000 kilometers in 5 hours. What is its average speed?
nlexa [21]

Given:

Total distance = 1000 kilometer

Total time = 5 hours

To find:

Average speed = ?

Formula used:

v_{avg} = \frac{s}{t}

Where v_{avg} = average speed

s = total distance

t = total time

Solution:

Average speed of the jet is given by,

v_{avg} = \frac{s}{t}

Where v_{avg} = average speed

s = total distance

t = total time

v_{avg} = \frac{1000}{5}

v_{avg} = 200 km/ h

Thus, average speed of the jet is 200 km/h.

Hence, Option (A) is correct.


7 0
3 years ago
Humans first traveled to the Moon in a spacecraft in 1969. What happened as the spacecraft traveled farther from Earth?
horsena [70]

Answer:

The answer is C)The force of gravity from Earth acting on the spacecraft decreased because the distance from Earth increased.

Explanation:

Gravity, a force, is dependent on the mass of the object exerting the gravity and the distance of an outside object from that object. The larger the object, the more gravity it will exert on an outside object. This force decreases as you move away from the object, but it will always still exist and never be equal to 0.

4 0
3 years ago
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Imagine that two balls, a basketball and a much larger exercise ball, are dropped from a parking garage. If both the mass and ra
pashok25 [27]

Here if we assume that there is no air friction on both balls then we can say

F = mg

now the acceleration is given as

F = ma = mg

a = g

so here both the balls will have same acceleration irrespective of size and mass

so we can say that to find out the time of fall of ball we can use

y = \frac{1}{2}gt^2

t = \sqrt{\frac{2y}{g}}

now from above equation we can say that time taken to hit the ground will be same for both balls and it is irrespective of its mass and size

3 0
3 years ago
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