All categories

3 years ago

2. 3m - 9n = 24 solve for m

Mathematics

1 answer:

const2013 [10]3 years ago

6 0

Answer:

m = 8 + 3n

Step-by-step explanation: there is an app called photo math it solves these problems instantly. I used it for this problem.

You might be interested in

When a customer wants pie for dessert, you cut whole pies into 7 equal slices. At the end of your shift, 3737 of a cherry pie, 2

matrenka [14]

the answer is 13/7 and here is the correct question

the answer is 13/7 and here is the correct questionwhen a customer wants pie for dessert you cut a whole pies into 7 equal slices...at the end of your shift 3/7 of. a cherry pie.2/7. of an apple pie.3/7 of a peach pie.and 5/7 of a blueberry pie remain...How much pie remains as a fraction of. a whole pie...

Answer:

13/7

Step-by-step explanation:

From the question, we have

3/7 of cherry pie

2/7 of apple pie

3/7 of peach pie

5/7 of blueberry pie

Now we have to add up all of these in order to get the total amount of pie

3/7 + 2/7 +3/7 +5/7

= (3+2+3+5)/7

=13/7

If expressed as a mixed fraction

= 1 6/7

In conclusion, 13/7 pie remains as a fraction of a whole.

4 0

2 years ago

Which of the following are NOT congruent?

algol13

the adjacent angles in a parallelogram

5 0

3 years ago

Can someone help me in this pretty please and asap!!! ;((

zepelin [54]

Answer:

(x -5)² + (y +4)² = 100 Should be the correct answer, hope this helps :)

Step-by-step explanation:

A circle centered at (h, k) with radius r will have equation ...

... (x -h)² + (y-k)² = r²

The point satisfies the equation for the circle. Filling in the given numbers, we have ...

... (x -5)² + (y+4)² = (-3-5)² + (2+4)² . . . . . . (h, k) = (5, -4), (x, y) = (-3, 2)

... (x -5)² + (y +4)² = 64 +36

6 0

2 years ago

The weight of an adult swan is normally distributed with a mean of 26 pounds and a standard deviation of 7.2 pounds. A farmer ra

Snezhnost [94]

Let $X$ denote the random variable for the weight of a swan. Then each swan in the sample of 36 selected by the farmer can be assigned a weight denoted by $X_1,\ldots,X_{36}$ , each independently and identically distributed with distribution $X_i\sim\mathcal N(26,7.2)$ .

You want to find

$\mathbb P(X_1+\cdots+X_{36}>1000)=\mathbb P\left(\displaystyle\sum_{i=1}^{36}X_i>1000\right)$

Note that the left side is 36 times the average of the weights of the swans in the sample, i.e. the probability above is equivalent to

$\mathbb P\left(36\displaystyle\sum_{i=1}^{36}\frac{X_i}{36}>1000\right)=\mathbb P\left(\overline X>\dfrac{1000}{36}\right)$

Recall that if $X\sim\mathcal N(\mu,\sigma)$ , then the sampling distribution $\overline X=\displaystyle\sum_{i=1}^n\frac{X_i}n\sim\mathcal N\left(\mu,\dfrac\sigma{\sqrt n}\right)$ with $n$ being the size of the sample.

Transforming to the standard normal distribution, you have

$Z=\dfrac{\overline X-\mu_{\overline X}}{\sigma_{\overline X}}=\sqrt n\dfrac{\overline X-\mu}{\sigma}$

so that in this case,

$Z=6\dfrac{\overline X-26}{7.2}$

and the probability is equivalent to

$\mathbb P\left(\overline X>\dfrac{1000}{36}\right)=\mathbb P\left(6\dfrac{\overline X-26}{7.2}>6\dfrac{\frac{1000}{36}-26}{7.2}\right)$
$=\mathbb P(Z>1.481)\approx0.0693$

5 0

2 years ago

Alguien me pone una foto de cuánto es 1,258 dividido entre 74 porfa :( Guarros

liq [111]

Como solo division?? Porque es 17

5 0

2 years ago

2. 3m - 9n = 24 solve for m​

2. 3m - 9n = 24 solve for m