Answer:
(-5,6)
Step-by-step explanation:
G(-5,4)=(x1,y1)
H(-5,8)=(x2, y2)
midpoint=?
now,
(x,y)= x1+x2/2 y1+y2/2
-5-5/2 4+8/2
-10/2 12/2
-5 6
therefore the co ordinates of midpoint are(-5,6)
Answer:
3
Step-by-step explanation:
12*0.75=9
To find this do 9/12.
4*0.75=y
y=3
<h2>Hey there!</h2><h2>

</h2><h2 /><h2>

</h2><h2>

</h2><h2>Good luck on your assignment and enjoy your day! </h2><h3>~
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</h3>
Answer:
x = 1/4 ± 1/4√233
Step-by-step explanation:
(2x + 5)(x - 3) = 14
~Use FOIL on the left side
2x² - 6x + 5x - 15 = 14
~Combine like terms
2x² - x - 15 = 14
~Subtract 14 to both sides
2x² - x - 29 = 0
~Use the quadratic formula and simplify
x = 1/4 ± 1/4√233
Best of Luck!
Answer:
None of these.
Step-by-step explanation:
Let's assume we are trying to figure out if (x-6) is a factor. We got the quotient (x^2+6) and the remainder 13 according to the problem. So we know (x-6) is not a factor because the remainder wasn't zero.
Let's assume we are trying to figure out if (x^2+6) is a factor. The quotient is (x-6) and the remainder is 13 according to the problem. So we know (x^2+6) is not a factor because the remainder wasn't zero.
In order for 13 to be a factor of P, all the terms of P must be divisible by 13. That just means you can reduce it to a form that is not a fraction.
If we look at the first term x^3 and we divide it by 13 we get
we cannot reduce it so it is not a fraction so 13 is not a factor of P
None of these is the right option.