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3 years ago

What’s the answer to question 19?

Mathematics

1 answer:

vaieri [72.5K]3 years ago

3 0

The answer to your question is “B” I’m not 100% sure but I’m pretty positive

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Daniel is constructing a fence that consists of parallel sides line AB and line EF. Complete the proof to explain how he can sho

Anit [1.1K]

Answer:

its 1

Step-by-step explanation:

got it right o the test

3 0

3 years ago

Each year for 4 years, a farmer increased the number of trees in a certain orchard by of the number of trees in the orchard the

Neko [114]

Answer:

The number of trees at the begging of the 4-year period was 2560.

Step-by-step explanation:

Let’s say that x is number of trees at the begging of the first year, we know that for four years the number of trees were incised by 1/4 of the number of trees of the preceding year, so at the end of the first year the number of trees was $x+\frac{1}{4} x=\frac{5}{4} x$ , and for the next three years we have that

Start End

Second year $\frac{5}{4}x$ -------------- $\frac{5}{4}x+\frac{1}{4}(\frac{5}{4}x) =\frac{5}{4}x+ \frac{5}{16}x=\frac{25}{16}x=(\frac{5}{4} )^{2}x$

Third year $(\frac{5}{4} )^{2}x$ ------------- $(\frac{5}{4})^{2}x+\frac{1}{4}((\frac{5}{4})^{2}x) =(\frac{5}{4})^{2}x+\frac{5^{2} }{4^{3} } x=(\frac{5}{4})^{3}x$

Fourth year $(\frac{5}{4})^{3}x$ -------------- $(\frac{5}{4})^{3}x+\frac{1}{4}((\frac{5}{4})^{3}x) =(\frac{5}{4})^{3}x+\frac{5^{3} }{4^{4} } x=(\frac{5}{4})^{4}x.$

So the formula to calculate the number of trees in the fourth year is

$(\frac{5}{4} )^{4} x,$ we know that all of the trees thrived and there were 6250 at the end of 4 year period, then

$6250=(\frac{5}{4} )^{4}x$ ⇒ $x=\frac{6250*4^{4} }{5^{4} }= \frac{10*5^{4}*4^{4} }{5^{4} }=2560.$

Therefore the number of trees at the begging of the 4-year period was 2560.

7 0

3 years ago

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lbvjy [14]

Answer:

$\sf \: \fbox{Option C) \: The salary of B is 6000₹}$

Step-by-step explanation:

Let the salary or A is x and salary of B is y.

now,

Condition one,The sum of 3/4th of A’s salary and 5/3rd of B’s salary is ₹16,000.

writing above statement in equation form,

$\sf \frac{3x}{4} + \frac{5y}{3} = 16000$

Multiplying above equation with twelve,

$\sf \frac{3x}{4} + \frac{5y}{3} = 16000 \\ \sf \frac{12 \times 3x}{4} + \frac{12 \times 5y}{3} = 16000 \times 12 \\ \sf \fbox{9x + 20y = 192000} \rightarrow eq. 1$

and condition two,

The difference of their salaries is ₹2000

$\sf \: x - y = 2000$

Multiplying above equation with 20

$\sf \fbox{\: 20x -20y = 40000} \rightarrow eq.2$

On adding equation 1 and equation 2,

$\sf9x + \cancel{20y} = 192000 \\ \sf 20x - \cancel{20y} = 40000 \\ \hline \sf 29x + 0y = 232000 \\ \sf x = \frac{232000}{29} \\ \sf \: \fbox{x = 8000₹}$

Substituting the value of x in,

$\sf \: x - y = 2000 \\ \sf \: 8000 - y = 2000 \\ \sf \: y = 8000 - 2000 \\ \sf \fbox{y = 6000₹}$

$\sf \: \fbox{The salary of B is 6000₹}$

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5 0

2 years ago

A farmer has 300 ft of fencing with which to enclose a rectangular pen next to a barn. The barn itself will be used as one of th

Katarina [22]

Let x represent the length of the side of the pen that is parallel to the barn. Then the area (y) will be
.. y = x(300 -x)/2
This describes a downward opening parabola with zeros at x=0 and x=300. The vertex (maximum) will be found at the value of x that is halfway between those, x = 150.

For that value of x, the pen area is
.. y = 150(300 -150)/2 = 150^2/2 = 11,250 . . . . . square feet.