PLEASE HELP!
2 answers:
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Answer:
See it in the pic.
Step-by-step explanation:
See it in the pic.
The formula for fractional exponents is ![\sqrt[n]{m} = x^{ \frac{m}{n} }](https://tex.z-dn.net/?f=%20%5Csqrt%5Bn%5D%7Bm%7D%20%3D%20%20x%5E%7B%20%5Cfrac%7Bm%7D%7Bn%7D%20%7D%20)
For this particular problem the expression would be written as![\sqrt[2]{ x^{3} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B2%5D%7B%20x%5E%7B3%7D%20%7D%20)
For this particular problem the expression would be written as
Answer:
0.7486 = 74.86% observations would be less than 5.79
Step-by-step explanation:
I suppose there was a small typing mistake, so i am going to use the distribution as N (5.43,0.54)
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
The general format of the normal distribution is:
N(mean, standard deviation)
Which means that:
What proportion of observations would be less than 5.79?
This is the pvalue of Z when X = 5.79. So
has a pvalue of 0.7486
0.7486 = 74.86% observations would be less than 5.79