Answer:
Resultant force, R = 10 N
Explanation:
It is given that,
Force acting along +x direction,
Force acting along +y direction,
Both the forces are acting on a point object located at the origin. Let the resultant force of the object is given by R. So,
Here
R = 10 N
So, the resultant force on the object is 10 N. Hence, this is the required solution.
Explanation :
It is given that,
Mass of the car, m = 1000 kg
Force applied by the motor,
The static and dynamic friction coefficient is,
Let a is the acceleration of the car. Since, the car is in motion, the coefficient of sliding friction can be used. At equilibrium,
So, the acceleration of the car is . Hence, this is the required solution.
Answer:
Explanation:
GIVEN
diameter = 15 fm =m
we use here energy conservation
there will be some initial kinetic energy but after collision kinetic energy will zero
on solving these equations we get kinetic energy initial
J ..............(i)
That is, the alpha particle must be fired with 35.33 MeV of kinetic energy. An alpha particle with charge q = 2 e
and gains kinetic energy K =e∆V ..........(ii)
by accelerating through a potential difference ∆V
Thus the alpha particle will
just reach the nucleus after being accelerated through a potential difference ∆V
equating (i) and second equation we get
e∆V = 35.33 Me V