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prohojiy [21]
4 years ago
5

What is velocity and acceleration?with examplesplzz and my question​

Physics
2 answers:
Anuta_ua [19.1K]4 years ago
7 0

Answer:velocity is defined as the displacement per unit time is called velocity. e. g

Acceleration is defined as the change of velocity of a body is called Acceleration. e. g if car moving with the constant velocity so Acceleration will be zero. If the velocity of car change so Acceleration also change.

The example of velocity is on picture...

Explanation:

posledela4 years ago
3 0

Answer:

the rate of change of displacement is named as velocity.it is a vector quantity                        

                                    VELOCITY=displacement/time

where the rate of change of velocity is named as acceleration

                                    ACCELERATION=velocity/time

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In order for work to take place the energy present must be related to the movement of the object.
kaheart [24]

This is another one of those muddy misleading questions, followed by
a muddy group of choices from which an answer must be selected.

a).  is absurd.  There's no such thing as a "balanced force", only
a balanced group of forces.

b).  is probably the choice the question is aiming for.

c).  is not so.  The engines of an airplane do plenty of work lifting the plane
off the ground, although the force of the engines is never directed upward.

d).  is really awkward.  The object's motion is almost never the cause of the force.
The force is almost always the cause of the object's motion.

Now for the big 800-lb gorilla in the room:  No moving object needs to be involved
in order for energy to be flowing or work to be getting done.

-- A radio wave radiates through space.  Straighten out a wire coat-hanger and
stick it up in the air where the radio wave can pass by it.  Electrical current flows
through the wire, and you can drain the electrical energy out the bottom of it.  

-- A light bulb is shining.  Some distance away, something it's shining on
gets warm, because of the heat energy that has shot across to it from the
light bulb and soaked into it.

-- A lightning bolt jumps from the ground to a passing cloud.  Or, if you feel
more comfortable with it, a lightning bolt jumps from a cloud to the ground.
It doesn't matter.  Either way, there's enough energy splashing around to
ignite houses, zap TVs and computers, melt concrete, vaporize water, and
light up a city.  Although nothing is moving.

5 0
3 years ago
The drum of a washing machine spins at 200 rpm the drum had a radius of 0.5m what will the centripetal force experienced by a to
miskamm [114]

The centripetal force experienced by the towel is 55 N.

The given parameters;

  • angular speed of the washing machine, ω = 200 rpm
  • radius of the machine' drum, r = 0.5 m
  • mass of the towel, m = 0.25 kg

The centripetal force experienced by the towel spinning along the walls of the drum is calculated as follows;

Fc = mrω²

where;

<em>Fc is the centripetal force</em>

<em>ω is angular speed in rad/s</em>

The angular speed in rad/s is calculate as;

\omega = \frac{200 \ rev}{\min} \times \frac{2\pi \ rad}{1 \ rev} \times \frac{1\min}{60 \ s} \\\\\omega = 20.95 \ rad/s

The centripetal force experienced by the towel is calculated as;

F_c = mr\omega ^2\\\\F_c = 0.25 \times 0.5 \times (20.95)^2\\\\F_c = 54.9 \ N \ \approx 55 \ N

Thus, the centripetal force experienced by the towel is 55 N.

Learn more here: brainly.com/question/20905151

5 0
3 years ago
Now imagine a person dragging a 50 kg box along the ground with a rope, as
ANTONII [103]

Answer:

The coefficient of static friction between the box and floor is, μ = 0.061

Explanation:

Given data,

The mass of the box, m = 50 kg

The force exerted by the person, F = 50 N

The time period of motion, t = 10 s

The frictional force acting on the box, f = 30 N

The normal force on the box, η = mg

                                                     = 50 x 9.8

                                                     = 490 N

The coefficient of friction,

                            μ = f/ η

                               = 30 / 490

                               = 0.061

Hence, the coefficient of static friction between the box and floor is, μ = 0.061

7 0
4 years ago
What time period is jellyfish first appear
const2013 [10]

According to scientists, the first fossil of a jellyfish first appeared approximately 500 million years ago. Or to be more exact, the Cambrian Period.

Hope I could help! :)

7 0
3 years ago
A 3.9 g dart is fired into a block of wood with a mass of 24.6 g. The wood block is initially at rest on a 1.5 m tall post. Afte
Galina-37 [17]

Answer:

46.48m/s

Explanation:

The problem is a combination of the principle of conservation of linear momentum and projectile motion.

The principle of conservation of linear momentum states that in a closed system, the total momentum of colliding bodies before impact is equal to the total momentum after impact. The masses stated in the problem experienced an inelastic collision. In an inelastic collision, the bodies involved stick together after the collision and move with a common velocity.

For two bodies of masses m_1 and m_2 moving with velocities u_1 and u_2 before impact, if they experience inelastic collision, the conservation of their momenta is as stated in equation (1);

m_1u_1+m_2u_2=(m_1+m_2)v..................(1)

were v is their common velocity after impact. If the second mass m_2 was at rest before the impact, then its initial velocity u_2=0m/s. therefore m_2u_2=0. Equation (1) then becomes;

m_1u_1=(m_1+m_2)v..............(2)

In the problem stated, the second mass taken as the mass of the wooden block was at rest before the impact and the collision was inelastic since both the wood and the dart stuck together and moved with a common velocity after the impact. Therefore we can use equation (2) for the problem.

Given;

m_1=3.9g=0.0039kg\\u_1=?\\m_2=24.6g=0.0246kg\\v=?

Substituting these values into (2), we get the following;

0.0039*u_1=(0.0039+0.024)v\\0.0039u_1=0.0285v.........(3)

Their common v velocity after impact now makes both the wooden block and the dart (as a single body) to fall vertically through a height h of 1.5m over a range R of 3.5m as stated by the problem; hence by the principle of projectile motion for a body projected horizontally, the following relationship holds;

R= vt............(4)

were t is the time taken to fall through the height h. To obtain t we use the second equation of free fall under gravity;

h=\frac{1}{2}gt^2...........(5)

were g is acceleration due to gravity taken as 9.8m/s^2. Therefore;

1.5=\frac{1}{2}*9.8*t^2\\1.5=4.9t^2\\t^2=\frac{1.5}{4.9}=0.306\\t=\sqrt{0.306} =0.55s

We then substitute R and t into equation (4) to obtain v.

3.5=v*0.55\\v=\frac{3.5}{0.55}\\v=6.36m/s

We now further substitute this value of v into (3) to obtain u_1;

u_1=\frac{0.0285v}{0.0039}\\\\u_1=\frac{0.0285*6.36}{0.0039}\\\\u_1=\frac{0.18126}{0.0039}\\\\u_1=46.48m/s

4 0
4 years ago
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