15. The

An Object is located 16 cm in front of a converging lens with focal length 12 cm. To the right of the converging lens, separated

ExtremeBDS [4]

Answer:

image is located at 22.5cm to the left of diverging lens.

Explanation:

In this question we have given,

object distance from converging lens,u=-16cm

focal length of converging lens, $f_{c}=12cm$

focal length of diverging lens, $f_{d}=-10cm$

distance between converging and diverging lens=20cm

we have to find location of final image,v=?

Here we will first find the location of image formed by converging lens

we know that u, v and $f_{c}$ are related by following formula

$\frac{1}{f_{c}} =\frac{1}{v}- \frac{1}{u}$ .............(1)

put values of $f_{c}$ and u in equation (1)

we got,

$\frac{1}{12} =\frac{1}{v}- \frac{1}{-16}$

$\frac{1}{12}-\frac{1}{16} =\frac{1}{v}$

$\frac{16-12}{16\times 12} =\frac{1}{v}$

or

$v=\frac{16\times 12}{16-12}\\ v=48cm$

The image is located 48 cm to the right of the converging lens. This image is real and inverted.

This image will object for the diverging lens which is now located (48-20=18) cm at the right hand side of diverging lens

it means,

u=18cm

we know that u, v and $f_{d}$ are related by following formula

$\frac{1}{f_{d}} =\frac{1}{v}- \frac{1}{u}$ .............(2)

put values of $f_{d}$ and u in equation (2)

$\frac{1}{-10} =\frac{1}{v}- \frac{1}{18}$

$\frac{1}{-10}+\frac{1}{18} =\frac{1}{v}$

$\frac{-18+10}{10\times 18} =\frac{1}{v}$

or

$v=\frac{10\times 18}{10-18}\\ v=-22.5cm$

It means image is located at 22.5cm to the left of diverging lens.

7 0

3 years ago

When acceleration and velocity are in opposing directions, the speed will

melamori03 [73]

Answer:

If the velocity and acceleration are in the same direction (both have the same sign - both positive or both negative) the object is speeding up. If the velocity and acceleration are in opposite directions (they have opposite signs), the object is slowing down.

<h2>Please mark my answer brainliest for further answers :)</h2>

8 0

3 years ago

Read 2 more answers

A musician playing a string instrument may use a finger to push a string tightly against the fingerboard of her instrument, thus

Thepotemich [5.8K]

Answer:

a) increase

Explanation:

The frequency of sound produced due to vibration of a string is governed by the following formula

n = 1/2L√T/m ;

L is length of the string in vibration, T is tension in the string and m is mass of string per unit length.

So frequency is inversely proportional to length of the string. Hence shortning of length of string increases the frequency of vibration.

7 0

3 years ago

The speed of a box traveling on a horizontal friction surface changes from vi = 13 m/s to vf = 11.5 m/s in a distance of d = 8.5

ValentinkaMS [17]

The average power supplied to the box by friction while it slows from 13 m/s to 11.5 m/s is 3.24 W.

<h3>Acceleration of the box</h3>

The acceleration of the box is calculated as follows;

vf² = vi² + 2as

a = (vf² - vi²)/2s

a = (11.5² - 13²) / (2 x 8.5)

a = -2.16 m/s²

<h3>Time of motion of the box</h3>

The time taken for the box to travel is calculated as follows;

a = (vf - vi)/t

t = (vf - vi) / a

t = (11.5 - 13) / (-2.16)

t = 0.69 s

<h3>Average power supplied by the friction</h3>

P = Fv

P = (ma)(vf - vi)

P = (1 x -2.16) x (11.5 - 13)

P = 3.24 W

Thus, the average power supplied to the box by friction while it slows from 13 m/s to 11.5 m/s is 3.24 W.

Learn more about average power here: brainly.com/question/19415290

#SPJ1

7 0

2 years ago

The light emitted by an argon laser light includes light with a wavelength of 488 nm. what is the frequency of this light? 6.15

Paraphin [41]

Frequency and wavelength are inversely related. That is, when frequency increases, the value of the wavelength decreases and vice versa. The constant of proportionality of the relation is the speed of light that has a value of 3.0x10^8 m/s. We calculate as follows:

wavelength = speed of light /frequency
488x10^-9 = 3.8x10^8 / frequency
frequency = 6.15x10^14 /s = 6.15x10^14 Hz ------> OPTION 3

3 0

4 years ago