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Scilla [17]
4 years ago
5

Please help me with chemistry. Thanks

Chemistry
2 answers:
il63 [147K]4 years ago
7 0
Constant:
Test tubes

Independent:
<span>volume of gas

Dependent:
</span>
<span>amount of H2O2 </span>
olga2289 [7]4 years ago
6 0
Hello there!

A constant stays the same so is the test tube.
An independent variable is changed to test the effects so is the volume of gas.
A dependent variable is being tested and so is the amount of H2O2.

Hope This Helps You!
Good Luck :)
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How many moles of na+ are present in 343 ml of a 1.27 m solution of na2so4?
cricket20 [7]
Sodium sulfate, Na₂SO₄, is a strong electrolyte. It means that it dissociates into 2 Na⁺ ions and 1 SO₄⁻ ion when dissolved in water. So, for every 1 mole of Na₂SO₄, there is an equivalent amount of 2 mol Na⁺ ions. The solution is as follows:

Moles of Na⁺ = (1.27 mol Na₂SO₄/L)*(1 L/1000 mL)*(343 mL)*(2 mol Na⁺/1 mol Na₂SO₄)
<em>Moles of Na⁺ = 0.87 mol</em>
4 0
4 years ago
"Crude oil dustillation"
liubo4ka [24]

Answer:

Crude oil is separated by fractional distillation. Crude oil is heated to vaporize the different hydrocarbons in a tank which is cool at the top and hot at the bottom. The vapours then rise and the different hydrocarbons condense at their specific boiling points, allowing them to be separated.

Lighter products, such as butane and other liquid petroleum gases (LPG), gasoline blending components, and naphtha, are recovered at the lowest temperatures. Mid-range products include jet fuel, kerosene, and distillates (such as home heating oil and diesel fuel).

5 0
2 years ago
Solid Al(NO3)3 is added to distilled water to produce a solution in which the concentration on nitrate, [NO3^-], is 0.10 M. What
VikaD [51]

Answer:

The concentration of nitrate ion NO_{3}^{-}  is 0.033 M.

Explanation:

Al(NO_{3})_{3} \rightarrow Al^{3+} + NO_{3}^{-}

1 mole of [Al^{3+}]  = 3 mole NO_{3}^{-}

Let  [NO_{3}^{-}]  = 3y

then according to above reaction,

[Al^{3+}] = y

[NO_{3}^{-}] = 0.10 M (given)

[Al^{3+}] = ?

3y = 0.10 M

y = \frac{0.1}{3}

y = 0.033 M

So ,concentration of [Al^{3+}] = y = 0.033 M

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3 years ago
Origin of name of aluminun
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From Latin word alumen, mean alum
3 0
3 years ago
How many molecules of carbon dioxide are present in 4.81042 mol of that substance?
Korvikt [17]

1 mol is equal to 6.02×10∧23 molecules.

first put in the calculator 4.81042 × 6.02 then hit EXP or 2nd then EE. (Depends on the type of calculator). then put in 23 and press equal.

The calculator will says 2.89587284×10∧24.

So the answer will be 2.90×10∧24.

I mot sure if the 2.90 is correct but it is close to the answer. it really depends how you want to round it. As long as the decimals are close the answer doesn't matter. Hope this helps. Please mark as Brainliest.

4 0
4 years ago
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