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stira [4]
3 years ago
8

The representative particle for nitrogen is:

Chemistry
2 answers:
koban [17]3 years ago
6 0
The representative particle for nitrogen is a molecule.
Marianna [84]3 years ago
3 0

Answer is: B/ a molecule

Hope this helps!

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K-12 Molar Mass<br> 7/10<br> Calculate the molar mass of aluminum nitrate, Al(NO3)3.<br> g/mol
tigry1 [53]
Molar mass = 212.996 g/mol

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You basically add the total atomic weight, these weights can be found on a periodic table
4 0
3 years ago
Why do you use 6.02*10^23 here?? #21???
almond37 [142]
6.02*10^23 is Avagadro's number representing the number of molecules per mole of substance.
6 0
3 years ago
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5) The properties of a substance depend on _______________
cluponka [151]

Answer:

(d) the atoms it contains and the way these atoms are connected

Explanation:

hope it will be helpful for you

3 0
3 years ago
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What is constant on wet asphalt?
wariber [46]

Answer:

Friction and Automobile Tires. ... On dry surfaces you might get as high as 0.9 as a coefficient of friction, but driving them on wet roads would be dangerous since the wet road coefficient might be as low as 0.1

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6 0
3 years ago
For the galvanic (voltaic) cell Fe(s) + Mn2+(aq) → Fe2+(aq) + Mn(s) (E°= 0.77 V at 25°C), what is [Fe2+] if [Mn2+] = 0.040 M and
avanturin [10]

Answer:

0.01836 M

Explanation:

Again the reaction equation is;

Fe(s) + Mn2+(aq) → Fe2+(aq) + Mn(s)

E°cell= 0.77 V

Ecell= 0.78 V

[Mn2+] = 0.040 M

[Fe2+] = the unknown

n=2

From Nernst's equation;

Ecell= E°cell- 0.0592/n log Q

0.78= 0.77 - 0.0592/2 log [Fe2+] /[0.040]

0.78-0.77= - 0.0592/2 log [Fe2+] /[0.040]

0.01/ -0.0296= log [Fe2+] /[0.040]

-0.3378= log [Fe2+] /[0.040]

Antilog(-0.3378) = [Fe2+] /[0.040]

0.459= [Fe2+] /[0.040]

[Fe2+] = 0.459 × 0.040

[Fe2+] = 0.01836 M

7 0
4 years ago
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