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3 years ago

What is the percent composition of CuO if a sample of CuO with a mass of 62.5 g contains 12.5 g of oxygen (O) and 50 g of Cu

Chemistry

1 answer:

Arlecino [84]3 years ago

7 0

Percent (%) Composition of CuO

Cu = 1 x 50g - Multiply by one as there is one Cu

O = 1 x 12.5g - Multiply by one as there is one O

CuO = 62.5g

% for Cu = 50g over 62.5 multiplied by 100 = 80%

% for O = 12.5g over 62.5 multiplied by 100 = 20%

Final Answer :

Percent (%) Composition of CuO = 80% (Cu) & 20% (O)

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Is h2c2o4 an Arrhenius base or arrhenius acid

maksim [4K]

Answer:
Oxalic Acid is and Arrhenius Acid.

Explanation:
According to Arrhenius Theory of acid and base, "Acid is any substance which when dissolved in water produces H⁺ Ions".

Therefore, Oxalic Acid is a diprotic substance, which is capable of donating protons in water. This acidity of oxalic acid can be dedicated to the stability of conjugate base, this stability comes from resonance of the negative charges on Oxalate ion. Below reaction shows the dissociation of Oxalic Acid into Protons and Oxalate Ion.

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3 years ago

Chemistry balance equations C2H +O2=CO2+H2O

son4ous [18]

Invalid equation.

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2 years ago

A buffer solution contains 0.486 M NaHCO3 and 0.345 M Na2CO3. If 0.0321 moles of sodium hydroxide are added to 150 mL of this bu

Molodets [167]

Answer:

pH = 10.51

Explanation:

The buffer of HCO₃⁻ + CO₃²⁻ has a pka of 10.2

HCO₃⁻ ⇄ H⁺ + CO₃²⁻

0,150L of these substances are:

0,150L × 0,486M NaHCO₃ = 0.0729mol NaHCO₃

0,150L × 0,345M Na₂CO₃ = 0.05175mol Na₂CO₃

NaOH reacts with HCO₃⁻ producing CO₃²⁻, thus:

NaOH + HCO₃⁻ → CO₃²⁻ + H₂O + Na⁺

0.0321 moles of NaOH produce the same moles of CO₃²⁻ and consume HCO₃⁻. Moles of these species are:

CO₃²⁻: 0.05175mol + 0.0321mol: 0.08385mol

HCO₃⁻: 0.0729mol - 0.0321 mol: 0.0408mol

Using Henderson-Hasselbalch formula:

pH = pka + log [Base] / [Acid]

pH = 10.2 + log 0.08385mol / 0.0408mol

pH = 10.51

I hope it helps!

7 0

3 years ago

Plz answer this for me...

Crank

Answer:

i can not help sorry

Explanation:

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3 years ago

1.) C6H12O6 (aq) is a(an)?

Marina86 [1]

Answer:

1) D. Dissolved Molecule

2) C. 11.30 M

Explanation:

Q1:

Glucose (C₆H₁₂O₆) is a non-polar molecule.

When it is dissolved in water, it will be a dissolved molecule.

It can not be ionized in water.

So, the right choice is: D. Dissolved molecule.

Q2:

The molarity is the no. of moles of dissolved solute in a 1.0 L of the solution.

M = (n)solute (1000/V (mL) of the solution)

n of LiCl = 2.60 mol, V = 230.0 mL.

∴ M = (n)solute (1000/V (mL) of the solution) = (2.60 mol)(1000)/(230.0 mL) = 11.30 M.

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3 years ago