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marusya05 [52]
3 years ago
13

What refers to the quantity of goods and services that consumers are willing to buy at a given price?

Mathematics
1 answer:
crimeas [40]3 years ago
4 0

Answer:

  "demand"

Step-by-step explanation:

Vocabulary question.

  "Demand" refers to the quantity of goods and services that consumers are willing to buy at a given price.

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Find the x intercepts of the parabola with vertex (-1,-16) and y intercept (0,-15)
Arlecino [84]
<span> first, write the equation of the parabola in the required form: </span>
<span>(y - k) = a·(x - h)² </span>

<span>Here, (h, k) is given as (-1, -16). </span>
<span>So you have: </span>
<span>(y + 16) = a · (x + 1)² </span>

<span>Unfortunately, a is not given. However, you do know one additional point on the parabola: (0, -15): </span>

<span>-15 + 16 = a· (0 + 1)² </span>
<span>.·. a = 1 </span>

<span>.·. the equation of the parabola in vertex form is </span>
<span>y + 16 = (x + 1)² </span>

<span>The x-intercepts are the values of x that make y = 0. So, let y = 0: </span>

<span>0 + 16 = (x + 1)² </span>
<span>16 = (x + 1)² </span>

<span>We are trying to solve for x, so take the square root of both sides - but be CAREFUL! </span>

<span>± 4 = x + 1 ...... remember both the positive and negative roots of 16...... </span>

<span>Solving for x: </span>
<span>x = -1 + 4, x = -1 - 4 </span>
<span>x = 3, x = -5. </span>

<span>Or, if you prefer, (3, 0), (-5, 0). </span>
8 0
3 years ago
To solve problems about spans of time that include B.C. and A.D. dates, you would need to use which numbers?
Studentka2010 [4]

The correct numbers to use in solving problems about spans of time like B.C. and A.D. should be “integers”.

Integers are whole numbers (not a fractional number or not a decimal number) which can take a value of negative, zero, or positive number. Example of integers would be -1, 0 and 1.

<span>In calculations, the time period would be on the x-axis. Since B.C. and A.D. are two different spans of time, therefore in the calculations, the date of BC should be negative (negative x-axis) while the date of AD should be positive (positive x-axis). This would place the origin as the common reference.</span>

3 0
3 years ago
Try and answer these multiple questions again and I will try to give you brainiest. Good Luck!
IrinaK [193]

Answer: 9: c  , 10: a ,11 :d  12: a

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
On the first day of travel, a driver was going at a speed of 40 mph. The next day, he increased the speed to 60 mph. If he drove
gogolik [260]

Velocity, distance and time:

This question is solved using the following formula:

v = \frac{d}{t}

In which v is the velocity, d is the distance, and t is the time.

On the first day of travel, a driver was going at a speed of 40 mph.

Time t_1, distance of d_1, v = 40. So

v = \frac{d}{t}

40 = \frac{d_1}{t_1}

The next day, he increased the speed to 60 mph. If he drove 2 more hours on the first day and traveled 20 more miles

On the second day, the velocity is v = 60.

On the first day, he drove 2 more hours, which means that for the second day, the time is: t_1 - 2

On the first day, he traveled 20 more miles, which means that for the second day, the distance is: d_1 - 20

Thus

v = \frac{d}{t}

60 = \frac{d_1 - 20}{t_1 - 2}

System of equations:

Now, from the two equations, a system of equations can be built. So

40 = \frac{d_1}{t_1}

60 = \frac{d_1 - 20}{t_1 - 2}

Find the total distance traveled in the two days:

We solve the system of equation for d_1, which gets the distance on the first day. The distance on the second day is d_2 = d_1 - 20, and the total distance is:

T = d_1 + d_2 = d_1 + d_1 - 20 = 2d_1 - 20

From the first equation:

d_1 = 40t_1

t_1 = \frac{d_1}{40}

Replacing in the second equation:

60 = \frac{d_1 - 20}{t_1 - 2}

d_1 - 20 = 60t_1 - 120

d_1 - 20 = 60\frac{d_1}{40} - 120

d_1 = \frac{3d_1}{2} - 100

d_1 - \frac{3d_1}{2} = -100

-\frac{d_1}{2} = -100

\frac{d_1}{2} = 100

d_1 = 200

Thus, the total distance is:

T = 2d_1 - 20 = 2(200) - 20 = 400 - 20 = 380

The total distance traveled in two days was of 380 miles.

For the relation between velocity, distance and time, you can take a look here: brainly.com/question/14307500

3 0
3 years ago
What is the unknown term.<br>in the seqpence 4.5, 5.4,____7.2<br><br>A.6.2 or B. 63​
harina [27]

Answer:

6.3

Explanation:

To get from 4.5 to 5.4, you need to add 0.9. If you add 0.9 two more times, you get 7.2. Therefore, the middle term should be 6.3. I don't know if you made a typo and forgot the decimal when writing the options cause it says "63", but I believe the answer is 6.3.

4 0
3 years ago
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