Answer:
y=5x-1 I think because the snd option doesn't make sense but you should try y =5x-1
Answer:
option-C
Step-by-step explanation:
We are given
At 9:00 a.m., a wind speed of 20 miles per hour was recorded
So, initial wind speed =20 miles per hour
Each measurement showed an increase in wind speed of 3 miles per hour
The strongest wind was recorded at 4:00 p.m
so,
top wind speed = initial wind speed + ( total number of hours between 9:00 am and 4:00 pm)*(change in wind speed)
top wind speed = 20 mph+(16-9)*3

miles per hour
Since, change in wind speed and initial wind speed are constant
but the number of hours it took for the wind speed to reach its minimum for the day can be changed
so, most important variables is
the number of hours it took for the wind speed to reach its minimum for the day can be changed
I we consider her running times as an arithmetic series with common difference:
43.13 - 43.1 = -.03/2 = -.015, Shelly's time in the fourth race will be 43.1 - .015 = 43.085.
Answer:
1 cubic centimeter
Step-by-step explanation:
V=l³ And l=1
so V=1³ so
V=1
since we cubed something it is in cubic centimeters so
1 cubic centimeter
Answer:
Step-by-step explanation:
When Riko left his house, Yuto was 5.25 miles along the path.
Average speed of Riko = 0.35 miles per minute
Average speed of Yuto = 0.25 miles per minute
First we will calculate the time in which Riko will catch Yuto on the track.
Relative velocity of Riko as compared to Yuto will be = velocity of Riko - velocity of Yuto
= 0.35 - 0.25
= 0.10 miles per minute
Now we this relative velocity tells that Riko is moving and Yuto is in static position.
By the formula,
Average speed = 
0.10 = 
t = 
t = 52.5 minutes
Now we know that Rico will catch Yuto in 52.5 minutes. Before this time he will be behind Yuto.
So duration of time in which Rico is behind Yuto will be 0 ≤ t ≤ 52.5
Here time can not be less than zero because time can not be with negative notation. It will always start from 0.