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3 years ago

Using the given zero, find one other zero of f(x). i is a zero of f(x).= x4 - 2x3 + 38x2 - 2x + 37.

Mathematics

2 answers:

Inessa [10]3 years ago

7 0

Answer:

-i

Step-by-step explanation:

Since the given function does not has any imaginary number.

And "i" is the imaginary number.So, other factor must be "-i" by conjugate rule.

Thus, One other factor is "-i".

For finding the other factors we will follow following steps:

The product of first and second factor is:

(x - i)(x + i) = x² - i² = x + 1

Now by dividing the given function f(x) = x⁴ - 2x³ + 38x² - 2x + 37 by (x + 1)

We get quadratic function. Then by Sidharyacharya Formula we will find other two factors.

oksian1 [2.3K]3 years ago

5 0

If i is a zero of the polynomial, then the factor is (x - i). Because of the conjugate rule, it is understood that one other root of the polynomial HAS to be (x + i). So that's one other root. The other 2 roots are (1 + 6i) and (1 - 6i).

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3/5x + 5 = 4/5<br>solve for x

Marysya12 [62]

Answer: x= -7

Step-by-step explanation:

3x/5 + 5 = 4/5

Put the fractions in 3x/5 +5 over a common denomintator.

7 0

3 years ago

If x2 mx m is a perfect-square trinomial, which equation must be true?.

kodGreya [7K]

Expression consist of numbers, variables, and mathematical operations. The equation that is true is x²+mx+m= (x+2)².

<h3>What is an Expression?</h3>

In mathematics, an expression is defined as a set of numbers, variables, and mathematical operations formed according to rules dependent on the context.

As it is given that the x²+mx+m is a perfect square trinomial, and we know that the general equation of perfect square trinomial is given as,

ax²+bx+c=0

where a,b and c are real numbers, and a≠0,

if we compare the equation with our equation

$ax^2+bx+c=0\\x^2+mx+m=0$

We will get the value of 'a' as 1, b=c=m, therefore, we need a binomial which is when expanded then in its perfect square trinomial the value of b=c, therefore, the only feasible option here is (x+2)².

Hence, the equation that is true is x²+mx+m= (x+2)².

Learn more about Expression:

brainly.com/question/13947055

7 0

2 years ago

90 POINTS PLEASE HELP

11111nata11111 [884]

$sin\alpha = - 0.8$

<u>Step-by-step explanation:</u>

We have , $cos\alpha = \frac{3}{5}$ , where $\alpha$ is located in IV quadrant! Let's find out value of $sin\alpha$ :

$sin\alpha = \sqrt{1-(cos\alpha )^2$

⇒ $sin\alpha = \sqrt{1-(cos\alpha )^2$

⇒ $sin\alpha = \sqrt{1-(\frac{3}{5} )^2$

⇒ $sin\alpha = \sqrt{1-(\frac{9}{25} )$

⇒ $sin\alpha = \sqrt{(\frac{25-9}{25} )$

⇒ $sin\alpha = \sqrt{(\frac{16}{25} )$

⇒ $sin\alpha = \pm {(\frac{4}{5} )$

Value of $sin\alpha$ is dependent on which quadrant it is . Since, in question it's given that $\alpha$ is located in IV quadrant , So $sin\alpha$ is negative i.e.

⇒ $sin\alpha = - {(\frac{4}{5} )$