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andrey2020 [161]
3 years ago
14

Harry owes the bank money. To repay his debt, he paid $150 back to the bank each month. After 10 months, his remaining debt was

$6900. What was the original amount of Harry's debt?
Mathematics
2 answers:
tino4ka555 [31]3 years ago
7 0

Answer:

$8400

Step-by-step explanation:

150 x 10 = 1500

$1500 + $6900 = $8400

zhenek [66]3 years ago
5 0

Answer: The original amount of his debt was $ 8,400

Step-by-step explanation:

Hi, to answer this question we have to write an equation

The original amount of his debt (x) minus the product of the amount he paid per month (150) multiplied by the number of months he paid (10) will be equal to the remaining debt (6900).

Mathematically speaking:

x - (150 x 10) = 6900  

Solving for x:

x- 1500 =6900

x = 6900+1500

x = $8,400

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Find the difference between 8/10 and -2 Show all calculations in your final answer.
valkas [14]
=2 4/5

8/10+2

2+8/10=2 8/10

4/5- -2/1

(4x1)-(-2x5) divided by 5x1

=4- -10 divided by 5

=14/5

=2 4/5

5 0
2 years ago
you have an initial amount of 55$ in a savings account and you deposit an equal amount into your account each week. After 6 week
sveticcg [70]
55+added=133
added=amount addeed per week times 6=6x

55+6x=133
minus 55 both sides
6x=78
divide both sides by 6
x=13

add 13 per week

y=13x+55
3 0
2 years ago
2TL
Ede4ka [16]

Answer:

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Step-by-step explanation:

7 0
2 years ago
Solve for y in -8×+4y=24
s344n2d4d5 [400]

Factor out the common term 4

-4(2x - y) = 24

Divide both sides by -4

2x-y= - 24/4

Simplify24/4 to 6

2x -y = -6

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-y = -6 - 2x

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5 0
3 years ago
WILL GIVE BRAINLIEST
jok3333 [9.3K]

Answer:

J'(-2,5)

K'(-7,5)

M'(-3.5,2)

L'(5.5,2)

Step-by-step explanation:

Please refer to the image attached to this answer.

Trapezoid JKLM is reflected over the x-axis, what do we notice about the ordered pairs of the original figure and the ordered pairs of its reflection over the x-axis is described below.

Point J , K L and M  , when reflected over x axis , there distance from the y axis remains the same in second quadrant. the x coordinate becomes negative however  the y coordinates remains the same.

The coordinates will be as shown in the image attached.

3 0
2 years ago
Read 2 more answers
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