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andrey2020 [161]
3 years ago
14

Harry owes the bank money. To repay his debt, he paid $150 back to the bank each month. After 10 months, his remaining debt was

$6900. What was the original amount of Harry's debt?
Mathematics
2 answers:
tino4ka555 [31]3 years ago
7 0

Answer:

$8400

Step-by-step explanation:

150 x 10 = 1500

$1500 + $6900 = $8400

zhenek [66]3 years ago
5 0

Answer: The original amount of his debt was $ 8,400

Step-by-step explanation:

Hi, to answer this question we have to write an equation

The original amount of his debt (x) minus the product of the amount he paid per month (150) multiplied by the number of months he paid (10) will be equal to the remaining debt (6900).

Mathematically speaking:

x - (150 x 10) = 6900  

Solving for x:

x- 1500 =6900

x = 6900+1500

x = $8,400

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3 years ago
How does graphing linear inequalities differ from graphing linear equations?​
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Explanation:

When the inequality symbol is replaced by an equal sign, the resulting linear equation is the boundary of the solution space of the inequality. Whether that boundary is included in the solution region or not depends on the inequality symbol.

The boundary line is included if the symbol includes the "or equal to" condition (≤ or ≥). An included boundary line is graphed as a solid line.

When the inequality symbol does not include the "or equal to" condition (< or >), the boundary line is not included in the solution space, and it is graphed as a dashed line.

Once the boundary line is graphed, the half-plane that makes up the solution space is shaded. The shaded half-plane will be to the right or above the boundary line if the inequality can be structured to be of one of these forms:

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Just as a system of linear equations may have no solution, so that may be the case for inequalities. If the boundary lines are parallel and the solution spaces do not overlap, then there is no solution.

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The attached graph shows an example of graphed inequalities. The solutions for this system are in the doubly-shaded area to the left of the point where the lines intersect. We have purposely shown both kinds of inequalities (one "or equal to" and one not) with shading both above and below the boundary lines.

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Step-by-step explanation:

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I'm guessing the sum is supposed to be

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Split the summand into partial fractions:

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1=a(5k+4)+b(5k-1)

If k=-\frac45, then

1=b(-4-1)\implies b=-\frac15

If k=\frac15, then

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This means

\dfrac{10}{(5k-1)(5k+4)}=\dfrac2{5k-1}-\dfrac2{5k+4}

Consider the nth partial sum of the series:

S_n=2\left(\dfrac14-\dfrac19\right)+2\left(\dfrac19-\dfrac1{14}\right)+2\left(\dfrac1{14}-\dfrac1{19}\right)+\cdots+2\left(\dfrac1{5n-1}-\dfrac1{5n+4}\right)

The sum telescopes so that

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and as n\to\infty, the second term vanishes and leaves us with

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