Answer:
b. fructose-1,6-bisphosphate
Explanation:
Pyruvate kinase is involved in last step of the process of glycolysis. The enzyme catalyzes transfer of the phosphate group from the phosphoenolpyruvate PEP to ADP and thus forming one molecule of the pyruvate and also, one molecule of ATP.
Glycolysis pathway is highly regulated at the three steps which are:
- Phosphorylation of the glucose by the enzyme, hexokinase.
- Phosphorylation of the fructose-6-phosphate by the enzyme, phosphofructokinase.
- Transfer of phosphate from phosphoenolpyruvate to ADP by the enzyme, pyruvate kinase.
All three of the reactions are irreversible in nature iunder wild-type conditions and thus have large negative free energy which are responsible for regulation of glycolysis pathway.
The activity of the enzyme, pyruvate kinase is mostly regulated by the allosteric effectors,by the covalent modifiers and also by the hormonal control.
<u>The most significant regulator for pyruvate kinase is fructose-1,6-bisphosphate that serves as allosteric effector for enzyme.</u>
<span>Double Displacement (Metathesis) hope this helps. </span>
Answer:
a) 0.13 bar
b) 5.05 L
Explanation:
Let us take the mass of the mixture to be 100 g. Hence, 70% by weight of dioxygen corresponds to 70 g
Mass of dihydrogen = 100g - 70 g = 30g
Number of moles of dioxygen = 70g/32 g/mol = 2.2 moles of dioxygen
Number of moles of dihydrogen = 30g/2g/mol = 15 moles of dihydrogen
Total number of moles = 2.2 + 15 = 17.2 moles
Mole fraction of dioxygen = 2.2/17.2 = 0.13
Partial pressure = mole fraction * total pressure
Partial pressure of dioxygen = 0.13 * 1 = 0.13 bar
ii) number of moles in 8.8 g of CO2 = 8.8g/44g/mol = 0.2 moles
T = 31.1 + 273 = 304.1 K
P = 1 bar
V= ?
R = 0.083 bar L K-1 mol-1
From
PV=nRT
V = nRT/P
V= 0.2 * 0.083 * 304.1/1
V= 5.05 L
Answer:
Robotic spacecrafts were sent to gather information about Halley’s comet, and the twin Voyagers gathered data from distant planets.
Explanation:
Where are the answers that apply .. hopes this help :)