Answer:
0.027 mole of NaOH.
Explanation:
We'll begin by obtaining the number of mole H2SeO4 in 45mL of 0.30M H2SeO4
This is illustrated below:
Molarity of H2SeO4 = 0.3M
Volume of solution = 45mL = 45/1000 = 0.045L
Mole of H2SeO4 =...?
Mole = Molarity x Volume
Mole of H2SeO4 = 0.3 x 0.045
Mole of H2SeO4 = 0.0135 mole
Next, the balanced equation for the reaction. This is given below:
H2SeO4 + 2NaOH –> Na2SeO4 + 2H2O
From the balanced equation above,
1 mole of H2SeO4 required 2 moles of NaOH.
Therefore, 0.0135 mole of H2SeO4 will require = 0.0135 x 2 = 0.027 mole of NaOH.
Therefore, 0.027 mole of NaOH is needed for the reaction.
Answer:
Ka2 values should be used in obtaining pKa2 in the Henderson–Hasselbalch equation
Explanation:
During first dissociation from H3PO4 to H2PO4-, ka1 will be used, and from H2PO4-to HPO4-, ka2 values will be used, hence a buffer solution containing H2PO4-and HPO4-will use ka2 in obtaining pKa2 in the Henderson–Hasselbalch equation.
Bond energy refers to the energy that must be taken in to break a bond. It is also the energy required to form the bond.
<h3>What is Bond energy?</h3>
The term bond energy refers to the energy that must be taken in to break a bond. It is also the energy required to form the bond.
The energy that must be supplied to break the bonds in two molecules of HCl is 862 J. The energy released is obtained from; 862J - [436 +262] = 164J.
The total energy of the reaction is 164J, this is called the enthalpy change. Based on this value of the total energy, the reaction is endothermic. Hence, it is true that; "It takes more energy to break the two H–Cl bonds than is released when forming the H–H and Cl–Cl bonds."
Learn more about bond energy:brainly.com/question/16754172?
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Answer:
a. True
Explanation:
The formula for determining the gold bromide formula, aqueous solution is added. When the solution is introduced with aluminum metal, the gold bromide reacts and displaces the gold metal. This is an electrolysis technique which is used for metals.
