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Vesna [10]
3 years ago
13

Match the items with the appropriate option.

Chemistry
1 answer:
tekilochka [14]3 years ago
6 0

Answer:

Breakdown of glucogen.

Glycogen phosphorylase of muscle and liver, which catalyzes the reaction

(Glucose)n + Pi ----> (glucose) n-1 + glucose 1-phosphate

Shortened glycogen chain

* acyl-CoA dehydrogenase

Dehydro genation of fatty acyl–CoA produces a double bond between the alpha and beta carbon atoms

Regulatory Enzyme of fatty acid breakdown

*Pyruvate dehydrogenase complex

Pyruvate derived from glucose and other sugars by glycolysis, is oxidized to acetyl-CoA and CO2 by the pyruvate dehydrogenase (PDH) complex, located in the mitochondria of eukaryotic cells and in the cytosol of bacteria.

Pyruvate converted to acetyl CoA

*Citrate synthase

The first reaction of the citric acid cycle is the condensation of acetyl-CoA with oxaloacetate to form citrate, catalyzed by citrate synthase:

Citric acid cycle.

* Lactate dehydrogenase

When animal tissues cannot be supplied with sufficient oxygen to support aerobic oxidation of the pyruvate and NADH produced in glycolysis, NAD+ is regenerated from NADH by the reduction of pyruvate to lactate.

Anaerobic respiration

*Phosphofructokinase

Glucose 6-phosphate can flow either into glycolysis or through any of several other pathways,

including glycogen synthesis and the pentose phosphate pathway. The metabolically irreversible reaction catalyzed by PFK-1 is the step that commits glucose to glycolysis.

Regulatory enzyme of glycolysis

*succinate dehydrogenase

Part of both the citric acid cycle and oxidative phosphorylation

*adenylate cyclase

Converts ATP to cAMP

*Glucose 6-phosphate dehydrogenase

Glucose 6-phosphate dehydrogenase catalyzes the first step in the pentose phosphate pathway, which produces NADPH.

Pentose phosphate pathway

*Glucose 6-phosphatase

Glucose 6-phosphate is dephosphorylated by glucose 6-phosphatase to yield free glucose.

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Answer:

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If 10.0 mL of a .600 M of HNO3 reacts with 31.0 mL of .700M Ba(OH)2 solution, what is the molarity of Ba(OH)2 after the reaction
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Answer:

<u></u>

  • <u>0.456M</u>

Explanation:

<u>1. Balanced molecular equation</u>

     2HNO_3+Ba(OH)_2\rightarrow Ba(NO_3)_2+2H_2O

<u>2. Mole ratio</u>

     \dfrac{2molHNO_3}{1molBa(OH)_2}

<u>3. Moles of HNO₃</u>

  • Number of moles = Molarity × Volume in liters
  • n = 0.600M × 0.0100 liter = 0.00600 mol HNO₃

<u>4. Moles Ba(OH)₂</u>

  • n = 0.700M × 0.0310 liter = 0.0217 mol

<u>5. Limiting reactant</u>

Actual ratio:

   \dfrac{0.0600molHNO_3}{0.0217molBa(OH)_2}\approx0.28

Since the ratio of the moles of HNO₃ available to the moles of Ba(OH)₂ available is less than the theoretical mole ratio, HNO₃ is the limiting reactant.

Thus, 0.006 moles of HNO₃ will react completely with 0.003 moles of Ba(OH)₂ and 0.0217 - 0.003 = 0.0187 moles will be left over.

<u>6. Final molarity of Ba(OH)₂</u>

  • Molarity = number of moles / volume in liters
  • Molarity = 0.0187 mol / (0.0100 + 0.0031) liter = 0.456M
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= 0.03653 moles
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