so, this is a quadratic equation, meaning two solutions, and we have a factored form of it, meaning you can get the solutions by simply zeroing out the f(x).
![\bf \stackrel{f(x)}{0}=-(x-3)(x+11)\implies 0=(x-3)(x+11)\implies x= \begin{cases} 3\\ -11 \end{cases} \\\\\\ \boxed{-11}\stackrel{\textit{\large 7 units}}{\rule[0.35em]{10em}{0.25pt}}-4\stackrel{\textit{\large 7 units}}{\rule[0.35em]{10em}{0.25pt}}\boxed{3}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7Bf%28x%29%7D%7B0%7D%3D-%28x-3%29%28x%2B11%29%5Cimplies%200%3D%28x-3%29%28x%2B11%29%5Cimplies%20x%3D%20%5Cbegin%7Bcases%7D%203%5C%5C%20-11%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5C%5C%20%5Cboxed%7B-11%7D%5Cstackrel%7B%5Ctextit%7B%5Clarge%207%20units%7D%7D%7B%5Crule%5B0.35em%5D%7B10em%7D%7B0.25pt%7D%7D-4%5Cstackrel%7B%5Ctextit%7B%5Clarge%207%20units%7D%7D%7B%5Crule%5B0.35em%5D%7B10em%7D%7B0.25pt%7D%7D%5Cboxed%7B3%7D)
so the zeros/solutions are at x = 3 and x = -11, now, bearing in mind the vertex will be half-way between those two, checking the number line, that midpoint will be at x = -4, so the vertex is right there, well, what's f(x) when x = -4?
![\bf f(-4)=-(-4-3)(-4+11)\implies f(-4)=7(7)\implies f(-4)=49 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \stackrel{vertex}{(-4~~,~~49)}~\hfill](https://tex.z-dn.net/?f=%5Cbf%20f%28-4%29%3D-%28-4-3%29%28-4%2B11%29%5Cimplies%20f%28-4%29%3D7%287%29%5Cimplies%20f%28-4%29%3D49%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20~%5Chfill%20%5Cstackrel%7Bvertex%7D%7B%28-4~~%2C~~49%29%7D~%5Chfill)
Answer:
A) 5
Step-by-step explanation:
The coefficients of the second equation are 1/3 of those of the first equation. If the constant of the second equation is also 1/3 of the constant of the first equation, then the equations are <em>dependent</em>, and will have an infinite number of solutions.
The constant must be something other than 1/3·15 = 5 to make the equations <em>inconsistent</em>, having no solutions.
Answer:
50 gluten-free cupcakes and 100 regular cupcakes.
Step-by-step explanation:
Let's define the variables:
R = number of regular cupcakes sold
G = number of gluten-free cupcakes sold
The total amount of money raised then is:
M = R*$2.00 + G*$3.00
We also know that:
The number of regular cupcakes sold was 2 times the number of gluten-free cupcakes sold.
then:
R = 2*G
And we also know that the amount of money raised is $350
Then we have the equations:
R = 2*G
R*$2.00 + G*$3.00 = $350
We can replace the first equation into the second one, so we have only one variable:
(2*G)*$2.00 + G*$3.00 = $350
Now we can solve this for G.
G*$4.00 + G*$3.00 = $350
G*$7.00 = $350
G = $350/$7.00 = 50
G = 50
50 gluten-free cupcakes where sold.
And using the equation:
R = 2*G = 2*50 = 100
We can conclude that 100 regular cupcakes were sold.
Hi there!
There is 1 3/4 doses, each with 1/4 teaspoons.
Could you please Brainliest me?
