7.025 is greater than 7 1/8
Answer:
log_4(256)=4
log_4(1/1024)=-5
log_4(16)=2
log_4(1/256)=-4
Step-by-step explanation:
We want to write a number, x, such that
Log_4(y)=x.
In exponential form that is 4^x=y.
So first number is x=4.
4^4=256 which means log_4(256) is 4 as a logarithm with base 4.
The second number is x=-5.
4^-5=1/4^5=1/1024 which means log_4(1/1024) is -5 as a logarithm with base 4.
The third number is x=2.
4^2=16 so log_4(16) is 2 as a logarithm with base 4.
The fourth number is x=-4.
Since 4^4=256 then 4^-4=1/256 which means -4 as a logarithm with base 4 is log_4(1/256).
Explanation
As you can see all the possible answers have the same form:

By looking at the picture you'll notice that the graph of g(x) has to pass through the point (2,1). Remember that the points in the graph of g(x) have the form (x,g(x)). Since (2,1) is part of the graph of g(x) then we have the following:

So let's evaluate the expression for g(x) that we wrote before at x=2. This way we'll obtain an equation for the number a:

Then we can divide both sides by 4:

Then we get:

Answer
Then the answer is option A.
No. The two lengths 5 and 5 add up to 10; you'd have two sides of length 5 each placed end to end, equaling 10. That'd be represented by segments on a straight line, not a triangle.
Hope you've drawn a picture, so as to understand this better. ;)