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My name is Ann [436]
3 years ago
12

suppose 25 out of 175 people said they like to play disc golf and out 5 out of every twelve of the players have a personalized b

lack disc at the Staybridge in a group of 252 people predict how many you would expect to have a personalized flying disc
Mathematics
1 answer:
Serhud [2]3 years ago
8 0
We have \frac{5}{12} of 252 people who have a personalized black disc

Number of people who would have personalized flying disc = \frac{5}{12}*252= \frac{2*252}{12}=105 people

Then we work out the number of people who like to play disc golf:
\frac{25}{175}*105= \frac{25*105}{175}=15 people

So we have 15 people who like to play disc golf and have personalised black disc.
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Renee adds 5 to a number, then multiplies the sum by-2. The result is 8. Write and solve an equation to find the number, x. What
miskamm [114]
5+(-9)= -4 • -2 =8
i hope i’m right.
5 0
3 years ago
(02.02 MC)
hoa [83]

So for the rhombus to carry onto itself, it needs to start in one position and end up in that same position. In this case, (x,y) will need to end up on (x,y) after the reflections are done. Here what the options do:

A: y-axis, x-axis, y-axis

(x,y) -> (-x,y) -> (-x,-y) -> (x,-y)

B: x-axis, y-axis, y-axis

(x,y) -> (x,-y) -> (-x,-y) -> (x,-y)

C: y=x, x-axis, y=x, y-axis

(x,y) -> (y,x) -> (y,-x) -> (-x,y) -> (x,y)

D: x-axis, y=x, x-axis, y=x

(x,y) -> (x,-y) -> (-y,x) -> (-y,-x) -> (-x,-y)

The only option that starts as (x,y) and ends as (x,y) is C: y=x, x-axis, y=x, y-axis, therefore making that the correct answer.

3 0
3 years ago
part b is: if the energy release of one earthquake is 10,000 times that of another, how much larger is the Richter scale reading
kotegsom [21]

You could use the information from part A to get B. I'm not sure if you want A or not, so I'll do it as well.

A

Eo = 10^4.4 Joules

E = 2 * 10^15

Formula

M = (2/3) log (E/Eo)

M = 2/3 * log (2 * 10^15/10^(4.4) )

M = 2/3 * log( 7.9621* 10^10)

M = 2/3 * 10.901

M = 7.26735 on the Richter scale. That is a huge amount of energy.

Part B

Suppose that you use Eo and your base. Eo is 10^4.4

Now the new earthquake is E = 10000 * Eo

So what you get now is M = (2/3)* Log(10000 * Eo / Eo )

The Eo's cancel out.

M = 2/3 * log(10000)

M = 2/3 of 4

M = 8/3

M = 2.6667 difference in the Richter Scale Reading. It is still an awful lot of energy.

What this tells you is that if the original reading was (say) 6 then the 10000 times bigger reading would 8.266667

Answer: M = 2.6667


8 0
3 years ago
Read 2 more answers
Can sombody please help me with this math problem?
Molodets [167]

y=2/3y-3


1. y = 2/3 (9)-3   multiply 9 and 2 =18/3

 y=18/3-3 divide 18 and 3 =6

y=6-3 subt. 3

y=3



2.  -11=2/3x - 3

 -11+3 = 2/3 x   add 3 to both sides to cancel -3

 -8=2/3 x  

(3/2)-8 = (2/3)3/2 x multiply both sides by reciprical of 2/3

-24/2 = x  divide

-12=x

4 0
3 years ago
Two angles are complementary. one of the angles is twice the other.the larger angle has a measure of
horrorfan [7]
Complimentary angles will add up to 90 degrees

x + y = 90
x = 2y

2y + y = 90
3y = 90
y = 90/3
y = 30......this is one angle

x = 2y
x = 2(30)
x = 60.....this is ur other angle

and ur larger angle is 60 degrees
7 0
3 years ago
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