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My name is Ann [436]
3 years ago
12

suppose 25 out of 175 people said they like to play disc golf and out 5 out of every twelve of the players have a personalized b

lack disc at the Staybridge in a group of 252 people predict how many you would expect to have a personalized flying disc
Mathematics
1 answer:
Serhud [2]3 years ago
8 0
We have \frac{5}{12} of 252 people who have a personalized black disc

Number of people who would have personalized flying disc = \frac{5}{12}*252= \frac{2*252}{12}=105 people

Then we work out the number of people who like to play disc golf:
\frac{25}{175}*105= \frac{25*105}{175}=15 people

So we have 15 people who like to play disc golf and have personalised black disc.
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4 years ago
The officers of a high school senior class are planning to rent buses and vans for a class trip. Each bus can transport 6363 ​st
attashe74 [19]

Answer:

  • 1 bus, 72 vans
  • $6960 is the minimum cost

Step-by-step explanation:

A bus costs over $19 per student; a van costs less than $12 per student. The required number of students could be transported by 81 vans, but that requires 81 chaperones.

Since there are only 80, and a bus requires fewer chaperones per student, we can reduce the number of required chaperones to an acceptable level by employing one bus. 1 bus replaces 9 vans, and requires 1 less chaperone than 9 vans.

The minimum cost is 1 bus and 72 vans. That cost is $1200 +72×$80 = $6960.

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3 years ago
Express 192 as the product of its prime factors write the prime factors in ascending order.
ira [324]

Answer:

Step-by-step explanation:I don't say u must have to mark my ans as brainliest but if it has really helped u plz don't forget to thank me...

4 0
3 years ago
In a sample of 230 teenagers, 202 would like to have smaller class sizes at their school. Find the sample
marishachu [46]

Answer:

The sample proportion is 0.88.

The margin of error is of 0.04.

The interval likely to contain the true population proportion is (0.84,0.92).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

Margin of error:

The margin of error is of:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

Sample of 230 teenagers, 202 would like to have smaller class sizes at their school.

This means that n = 230, and that the sample proportion is:

\pi = \frac{202}{230} = 0.88

The sample proportion is 0.88.

Standard 95% confidence level

So \alpha = 0.05, z is the value of Z that has a p-value of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

Margin of error:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

M = 1.96\sqrt{\frac{0.88*0.12}{230}}

M = 0.04

The margin of error is of 0.04.

Confidence interval:

Sample proportion plus/minus margin of error. So

0.88 - 0.04 = 0.84

0.88 + 0.04 = 0.92

The interval likely to contain the true population proportion is (0.84,0.92).

5 0
3 years ago
What is the solution for the quadratic equation?
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