Answer:
52÷(13x2) 13×2 = 26 52÷26=2
Frequency is the Number of Waves passing through a Point in One Second
Given : The Frequency of the Wave is : 700 Hz
Given : The Wavelength of the Wave is : 6 meter
⇒ In One second 700 waves of Wavelength 6 meter cross the point
⇒ In One second the First wave travels : 700 × 6 meters
⇒ In One second the First wave travels : 4200 meter
⇒ The Speed of the wave is : 4200 m/sec
Answer:

Step-by-step explanation:
<u>Function Modeling</u>
Since the air in the lungs goes periodically from a minimum value to a maximum value, we can simulate its behavior as a sinusoid. Selecting a sine or a cosine will depend on the initial condition we'll assume since the question doesn't provide one. We'll set the initial state when the lungs are at maximum air content. The sinusoid that starts from maximum is the cosine, so our model is

Where Ao is the amplitude of the oscillation, w is the angular frequency and M is the midline or y-displacement of the wave.
The values of A run from a min of 3.5 to a max of 4.5. That gives us twice the amplitude, thus

The vertical displacement or midline can be found as the shift from the center value:

We also know the cycle repeats 6 times per minute. If the time is expressed in minutes, then the frequency is f=6
Knowing that

Then

The model is

where t is expressed in minutes
T's going to make a difference whether that 4 percent is compounded more
<span>than once a year. </span>
<span>We'll do the calculation assuming it's compounded only once a year, and if it </span>
<span>turns out to be compounded more often than that, then the calculation will </span>
<span>come out on the low side, and you'll wind up with a little bit more than $3,000. </span>
P<span> times (1.04)</span>3<span> = $3,000 </span>
P<span> = </span>3,000/<span>(1.04)3</span><span> = $2,666.980769 or </span><span>$2,667</span>