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oksano4ka [1.4K]
3 years ago
13

PLEASE ASAP!!! Describe the graph of a system of two linear inequalities that have no solution.

Mathematics
1 answer:
Kitty [74]3 years ago
7 0
The lines will not intersect
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(n 4 - 2n 3 - 3n 2 + 7n - 2) ÷ (n - 2)
GrogVix [38]
I believe it's 

- 1 - \frac{4}{n - 2}

Hope I helped! ( Smiles )
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A function is described by the function notation f(x) = 2x' +1. Which shows a correct pairing of
salantis [7]
The answer to you’re question is H
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0.3(3a-4)-0.05(8a)(-7a)
Anit [1.1K]

Answer:

2.8a²+0.9a - 1.2

Step-by-step explanation:

Given the expression 0.3(3a-4)-0.05(8a)(-7a)

Expand using the distributive law

0.3(3a-4)-0.05(8a)(-7a)

0.3(3a)-0.3(4)-0.05(8a)(-7a)

0.9a-1.2 - 0.05(8a)(-7a)

0.9a - 1.2 + 2.8a²

Rearrange

2.8a²+0.9a - 1.2

Hence the required expression is 2.8a²+0.9a - 1.2

3 0
2 years ago
Which is the sum of -4 and its additive inverse?
Aneli [31]

Answer:

-4 +4 =0

Step-by-step explanation:

The sum of a number and its' additive inverse is 0

The additive inverse of -4 is 4

-4 +4 =0

3 0
2 years ago
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Consider a value to be significantly low if its z score less than or equal to minus−2 or consider a value to be significantly hi
ziro4ka [17]

Answer:

If the weight is higher than 5.8886 gr would be considered significantly high

If the weight is lower than 5.6121 gr would be considered significantly low

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

X \sim N(5.75241,0.06281)  

Where \mu=5.75241 and \sigma=0.06281

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

For the case when z =-2 we can do this:

-2 = \frac{X-5.75241}{0.06281}

And if we solve for X we got:

X = 5.75241 -2*0.06281 =5.6121

And for the other case when Z=2 we have:

2 = \frac{X-5.75241}{0.06281}

And if we solve for X we got:

X = 5.75241 +2*0.06281 =5.8886

If the weight is higher than 5.8886 gr would be considered significantly high

If the weight is lower than 5.6121 gr would be considered significantly low

5 0
3 years ago
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