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zhenek [66]
4 years ago
6

Classify each number as rational or irrational.

Mathematics
2 answers:
Sonja [21]4 years ago
7 0
0.167 is rational
2/9 is rational
225 is rational
Pi is irrational
Ugo [173]4 years ago
3 0

Answer:

0.167 - rational number

29 -  rational number.

\pi - irrational number

\sqrt{225} - rational number

Step-by-step explanation:

Rational numbers can be written as a fraction or whole numbers. It can be positive or a negative number

0.167 (repeating decimal) can be represented as a simple fraction

So it is a rational number

29 is an integer. So it is a rational number.

\pi cannot be written in simple fractional form so it is an irrational number

\sqrt{225} = 15 is a rational number

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svetoff [14.1K]

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after the decimal point each number from left to right is written with "-ths" at the end

like

10 = 1 tens

0.1 = 1 tenths

4 0
3 years ago
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Natali [406]

Answer:

Step-by-step explanation:

3 0
3 years ago
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Umnica [9.8K]

Answer:8(10+2)

8(10+2)

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I hope this is good enough:

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3 years ago
Which scatter plot shows a definite non-linear relationship between x and y?
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6 0
3 years ago
A sequence is defined by f(0) = -20, f(n) = f(n-1) - 5 forn &gt; 1.
bulgar [2K]

Answer:

1. Proved down

2. proved down

3. f(10) = -20 - 5 - 5 - 5 - 5 - 5 - 5 - 5 - 5 - 5 - 5

Step-by-step explanation:

Let us explain how to solve the question

∵ f(0) = -20, f(n) = f(n - 1) - 5 for n > 1

→ That means we have an arithmetic sequence with constant

   difference -5 and first term -20

1. → f(1) means we need to find the second term, which equal the

      term - 5

∵ f(1) means n = 1

∴ f(1) = f(1 - 1) - 5

∴ f(1) = f(0) - 5

∵ f(0) = -20

∴ f(1) = -20 - 5 → Proved

2. → f(3) means we need to find the third term, which equal the

   second term - 5

∵ f(3) means n = 3

∴ f(3) = f(3 - 1) - 5

∴ f(3) = f(2) - 5

→ f(2) = f(1) - 5

∵ f(1) = -20 - 5

∴ f(2) = [-20 - 5] - 5 = -20 - 5 - 5

∴ f(3) = [-20 - 5 - 5] - 5

∴ f(3) = -20 - 5 - 5 - 5 → Proved

3. → From 1 and 2 we notice that the number of -5 is equal to n,

      at n = 1 there is one (-5), when n= 3 there are three (-5)

∵ n = 10

∴ There are ten (-5)

∴ f(10) = -20 - 5(10)

∴ f(10) = -20 - 5 - 5 - 5 - 5 - 5 - 5 - 5 - 5 - 5 - 5 → Proved

6 0
3 years ago
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