<span>ΔT for the first sample is the total samples final temp, minus the first sample's initial temp (47.9-22.5), so 25.4oC.
Calculating q for the first sample as 108g x 4.18 J/g C x 25.4oC = 11466.58 Joules
Figuring that since the first sample gained heat, the second sample must have provided the heat, so doing the calculation for the second sample, I used
q=mCΔT
11466.58 Joules = 65.1g x 4.18 J / g C x ΔT
11466.58/(65.1gx4.18)=ΔT
ΔT=42.14oC
So, since second sample lost heat, it's initial temperature was 90.04oC (47.9oC final temperature of mixture + 42.14oC ΔT of second sample).</span>
Answer:
r=2.743
Explanation:
The energy stored on a capacitor is of type potencial, therfore depends on the capacity to "store" energy. Inthe case of the capacitor, it stores charge (Q), and the equations you use to calculate it are:
In this case we know V and C, therefore we use the last expression:
r=2.743
Density is a chemichal change
C. added an electron to the outer electron shell.
Explanation:
Atoms consist of three particles:
- Protons: they are located in the nucleus, they have positive charge of , and mass of
- Neutrons: they are also located in the nucleus, they have no electric charge, and mass similar to that of the proton
- Electrons: they orbit around the nucleus, they have negative charge of , and mass around 1800 smaller than the proton
Normally, atoms are neutral (no electric charge), because they have an equal number of protons and electrons.
However, sometimes atoms can give off or take electrons from other atoms. We have two cases:
- If an atom gives off an electron, it remains with an excess of positive charge, so it becomes a positive ion
- If an atom takes an electron from another atom, it remains with an excess of negative charge, so it becomes a negative ion
Therefore, in order to form a negative ion, the atom must have
C. added an electron to the outer electron shell
Learn more about atoms:
brainly.com/question/2757829
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