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D = m / V
13.6 = 76.2 / V
V = 76.2 / 13.6
V = 5.602 mL
Answer:
The answer is C. Organ systems please brainly me!
Explanation:
Answer:
[Ne]3s2
Explanation:
ahora tenemos que mirar cada una de las configuraciones electrónicas de cada átomo de cerca antes de tomar una decisión.
considerando la configuración electrónica más externa de cada una de las especies mostradas;
para la primera configuración, ns2 np6 corresponde a un gas noble.
para la segunda configuración ns2 np3 corresponde a un elemento no metálico del grupo 5.
para la tercera configuración, ns2 corresponde a un elemento metálico del grupo 2.
para la cuarta configuración, ns2 np4 corresponde a un elemento no metálico del grupo 6
Answer:
The clouds that carry the dust can be huge, and miles long. They can rise to be over 305m. They also have wind speeds of at least 40 kilometers.Sandstorms can happen really quickly.
Explanation:
Sandstorms carry with them large volumes of sand and dust. But more than sand, they also carry with them virus spores that interact with the atmosphere. Because of this, I can contact any disease from it.
Other immediate effects of sandstorms to me include the worsening of lung functions if I have asthma. Due to inhalation of large amounts of dust, dust pneumonia could be developed. Diseases such as silicosis could also develop from prolonged exposure to sand. If left untreated, it will eventually lead to asphyxiation and lung cancer. The eyes could also be affected by the particles. Keratoconjunctivitis sicca, or dry eyes, could develop which could lead to blindness. My exposure to sandstorms could have adverse effects on my circulatory system. So I could either die immediately or fall terrible sick it depend on my health issue.
The amount in grams of Al₂O₃ produced is approximately 6.80 g.
Aluminium reacts completely with oxygen(air) to produce Al₂O₃. The reaction can be represented with a chemical equation as follows:
AL + O₂ → Al₂O₃
Let's balance it
4AL + 3O₂ → 2Al₂O₃
4 moles of Aluminium reacts with 3 moles of Oxygen molecules to produce 2 moles of Aluminium oxide. Therefore,
Since, aluminium reacts completely, it is the limiting reagent in the reaction. Therefore,
Atomic mass of AL = 27 g
Molar mass of Al₂O₃ = 101.96 g/mol
4(27 g) of AL gives 2(101.96 g) of Al₂O₃
3.6 g of AL will give ?
cross multiply
mass of Al₂O₃ produced = 3.6 × 203.92 / 108 = 734.112 / 108 = 6.797
mass of Al₂O₃ produced = 6.80 g.
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