Answer:
Hey mate......
Explanation:
This is ur answer......
<h3>
The Law of Conservation of Mass</h3>
<em>Matter can change form through physical and chemical changes, but through any of these changes, matter is conserved. The same amount of matter exists before and after the change—none is created or destroyed. This concept is called the Law of Conservation of Mass.</em>
<em>The Law of Conservation of Matter also states that the matter cannot be created or destroyed. In a physical change, substances can change form, but the total mass remains the same. In a chemical change, the total mass of the reactants always equals the total mass of the products.</em>
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Answer:
gravity pull stuff down...
Explanation:
1, they were wrong sometimes
2. people don't trust him
According to the reaction, when 355 ml of 1.65 m Hydrochloric acid solution are combined with too much aluminum, 26.03 g of aluminum chloride is created.
An inorganic substance with the formula AlCl3 is aluminum chloride, also referred to as aluminum trichloride. It takes the form of [Al(H2O)6] hexahydrate. Aluminum chloride is ALCl3, which is composed of six water molecules. Aqueous hydrochloric acid, also referred to as muriatic acid, is a type of hydrochloric acid. It is a colourless solution with an overpowering odor. Strong acid is how it is categorized.
2 Al(s) + 6 HCl is the given reaction. ———-> 2 AlCl3 + 3H2
Using the provided data
The amount of HCl in moles is n= Volume * Concentration = 0.58575 mol (1.65 M * 355 ml)/1000 ml
based on the response,
It takes 6 mols of HCl. To neutralize 2 moles of aluminum, 0.58575 mol of hydrochloric acid must be used.
using the cross-multiplication method, 0.19525 moles are obtained by multiplying 0.58575% by 2/ 6.
Weight of the AlCl3 = 0.1952 moles * 133.340538 g/mol = 26.03 g
Learn more about Hydrochloric acid here
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Answer:
150 g/mol
Explanation:
Let's consider the complete neutralization of a diprotic acid H₂X with NaOH.
H₂X + 2 NaOH → Na₂X + 2 H₂O
40.0 mL of 0.200 M NaOH. were required to reach the endpoint. The reacting moles of NaOH are:
0.0400 L × 0.200 mol/L = 8.00 × 10⁻³ mol
The molar ratio of H₂X to NaOH is 1:2. The reacting moles of H₂X are 1/2 × 8.00 × 10⁻³ mol = 4.00 × 10⁻³ mol.
4.00 × 10⁻³ moles of H₂X have a mass of 0.600 g. The molar mass of H₂X is:
0.600 g/4.00 × 10⁻³ mol = 150 g/mol
