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REY [17]
3 years ago
14

Ashley had a summer lemonade stand where she sold small cups of lemonade for 41.25 AND LARGE CUPS FOR $2.50. If Ashley solf a to

tal of 155 cups of lemonade for $265, how many cups of each tpe did she sell?
Mathematics
1 answer:
Rama09 [41]3 years ago
6 0

Question:

Ashley had a summer lemonade stand where she sold small cups of lemonade for $1.25 and large cups for $2.50. If Ashley sold a total of 155 cups of lemonade for $265, how many cups of each did she sell

Answer:

The number of small cups of lemonades  is 98

The number of Large cups of lemonades is 57

Step-by-step explanation:

Given:

Cost of small lemonade  cups = $1.25

Cost of large Lemonade cups =  $2.50

Total number of lemonade cups  = 155 cups

The total cost for which the lemonade is sold =  $265

To Find:

Number of each types of lemonade sold = ?

Solution:

Let the number of small cups of lemonade sold be x

the number of large cups of lemonade sold be y

Then according to the question,

x+y = 155-----------------------------(1)

Then the amount earned by  selling small and large lemonade cups is $265

Then

1.25x+2.50y = 265------------------(2)

From (1)

y = 155-x----------------------------------(3)

Substituting (3) in (2), we get

1.25x+ (155-x)2.50 = 265

1.25 + (387.5 -2.50x) =265

-1.25x + 387.5 = 265

-1.25x= 265 -387.5

-1.25x =  -122.5

x = \frac{-122.5}{-1.25}

x= 98--------------------------------(4)

Substituting (4) in (3)

y = 155-98

y =57

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Taya2010 [7]

Using the binomial distribution, it is found that the variance of the number that pass inspection in one day is 5.7.

For each component, there are only two possible outcomes, either it passes inspection, or it does not. The probability of a component passing inspections is independent of any other component, hence, the binomial distribution is used to solve this question.

Binomial probability distribution

Probability of <u>exactly x successes on n repeated trials, with p probability</u>, and has variance given by:

V(X) = np(1 - p)

In this problem:

  • 95% pass final inspection, hence p = 0.95
  • 120 components are inspected in one day, hence n = 120.

The variance is given by:

V(X) = np(1 - p) = 120(0.95)(0.05) = 5.7

The variance of the number that pass inspection in one day is 5.7.

To learn more about the binomial distribution, you can take a look at brainly.com/question/24863377

3 0
2 years ago
Determine the missing number in the equation 13-2=12-?​
soldier1979 [14.2K]

For the equation to work, you have to have the same number on both sides of the equal sign

so to find ?, you can do:

13 - 2 = 12 - ?       Simplify

11 = 12 - ?       Subtract 12 on both sides

-1 = - ?     Multiply -1 on both sides

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5 0
3 years ago
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Mrac [35]
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2 years ago
The product of (3 + 2i) and a complex number is (17 + 7i).
Vesna [10]
A+bi is a complex number

(3+2i)(a+bi)=17+7i
remember
i²=-1
so
expand and solve
a is the ral part
bi is the imaginary part
ok so
if Ac+Be=dc+fe where c=c and e=e then A=d and B=f

(3+2i)(a+bi)=17+7i
expand/distribute/FOIL
3a+2ai+3bi+2bi²=17+7i
3a+2bi+2ai+2bi=17+7i
3a-2b+2ai+2bi=17+7i
real parts are 3a-2b
imaginary is 2ai+2bi
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3a-2b=17 and
2ai+2bi=7i

we need to solve
2nd equation, divide both sides by i
2a+2b=7
multiply by -1 and add to other equation

3a+2b=17
<u>-2a-2b=-7 +</u>
1a+0b=10
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subsitue
2a+2b=7
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2b=-13
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Irina-Kira [14]

Answer:

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Step-by-step explanation:

There is an easy way to work this. Divide the miles he drove by 2 so that you know how much he drove in 1/5 hours.

29/2= 14.5miles driven in 1/5 hours

Now, just multiply that number by 5 so that you know how many miles he drove in 5/5 hours (one full hour).

14.5*5= 72.5miles

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