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liq [111]
3 years ago
14

The half-life for the radioactive decay of ce−141 is 32.5 days. if a sample has an activity of 3.8 μci after 162.5 d have elapse

d, what was the initial activity, in microcuries, of the sample?
Chemistry
2 answers:
Umnica [9.8K]3 years ago
5 0
Answer : 121.5 <span>μCi

Explanation : We have Ce-141 half life given as 32.5 days so if the activity is 3.8 </span><span>μci after 162.5 days of time elapsed we have to find the initial activity.

We can use this formula;

</span>\frac{N}{ N_{0} } =  e^{-( \frac{0.693 X  T_{2} }{T_{1}})

3.8 / N_{0} = e^ ((0.693 X 162.5 ) / 32.5) = 121.5
<span>
On solving we get, The initial activity as 121.5  </span>μci
padilas [110]3 years ago
5 0

Answer : The initial activity, in microcuries, of the sample was, 120.9 μci

Explanation :

Half-life = 32.5 days

First we have to calculate the rate constant, we use the formula :

k=\frac{0.693}{t_{1/2}}

k=\frac{0.693}{32.5\text{ days}}

k=0.0213\text{ days}^{-1}

Now we have to calculate the time passed.

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 0.0213\text{ days}^{-1}

t = time passed by the sample  = 162.5 days

a = initial amount of the reactant  = ?

a - x = amount left after decay process = 3.8 μci

Now put all the given values in above equation, we get

162.5=\frac{2.303}{0.0213}\log\frac{a}{3.8\mu ci}

a=120.9\mu ci

Therefore, the initial activity, in microcuries, of the sample was, 120.9 μci

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using the formula PV=nRT should be used to solve for the number of moles (n).  R is a constant which is 62.3637 L mmHG/mole K.

Inorder for your units to match you will have to convert 125ml to .125L and the temperature of 85C to K . you do that by adding 273 to the 85C and get 358K.  Once you solve for n then you use that number and divide by the number of grams from the question (.560g) since molar mass is grams/moles.

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How many of the following statements about silver acetate, AgCH3COO, are true? i) More AgCH3CoO(S) will dissolve if the pH of th
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All three statements are true

Explanation:

Solubility equilibrium of silver acetate:

AgCH_{3}COO\rightleftharpoons Ag^{+}+CH_{3}COO^{-}

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Calculate the heat energy required to melt 4kg of ice when the specific latent heat of fusion of water is 334,000 J/kg.
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Taking into account the definition of calorimetry and latent heat, the heat energy required to melt 4 kg of ice when the specific latent heat of fusion of water is 334,000 \frac{J}{kg} is 1,336 kJ.

<h3>Calorimetry</h3>

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

<h3>Latent heat</h3>

Latent heat is defined as the energy required by a quantity of substance to change state.

When this change consists of changing from a solid to a liquid phase, it is called heat of fusion and when the change occurs from a liquid to a gaseous state, it is called heat of vaporization.

The heat Q that is necessary to provide for a mass m of a certain substance to change phase is equal to

Q = m×L

where L is called the latent heat of the substance and depends on the type of phase change.

<h3>Heat energy required to melt ice</h3>

In this case, you know:

  • m= 4 kg
  • L= specific latent heat of fusion of water= 334,000 \frac{J}{kg}

Replacing in the expression for latent heat:

Q = 4 kg× 334,000 \frac{J}{kg}

Solving:

<u><em>Q= 1,336,000 J= 1,336 kJ </em></u>(being 1,000 J= 1 kJ)

Finally, the correct answer is the first option: the heat energy required to melt 4 kg of ice when the specific latent heat of fusion of water is 334,000 \frac{J}{kg} is 1,336 kJ.

Learn more about calorimetry:

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