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sukhopar [10]
3 years ago
14

I need help with this

Chemistry
2 answers:
slega [8]3 years ago
8 0

Answer:

b

Explanation:

N76 [4]3 years ago
3 0
B- the same substance with different properties were formed
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N₂O(g) + 3 H₂(g) N₂H4(1) + H₂O(1) AH = -317 kJ/mol
docker41 [41]

Answer:

A

Explanation:

Recall that Δ<em>H</em> is the sum of the heats of formation of the products minus the heat of formation of the reactants multiplied by their respective coefficients. That is:


\displaystyle \Delta H^\circ_{rxn} = \sum \Delta H^\circ_{f} \left(\text{Products}\right) - \sum \Delta H^\circ_{f} \left(\text{Reactants}\right)

Therefore, from the chemical equation, we have that:


\displaystyle \begin{aligned} (-317\text{ kJ/mol}) = \left[\Delta H^\circ_f \text{ N$_2$H$_4$} +  \Delta H^\circ_f \text{ H$_2$O}  \right]   -\left[3 \Delta H^\circ_f \text{ H$_2$}+\Delta H^\circ_f \text{ N$_2$O}\right] \end{aligned}

Remember that the heat of formation of pure elements (e.g. H₂) are zero. Substitute in known values and solve for hydrazine:

\displaystyle \begin{aligned} (-317\text{ kJ/mol}) & = \left[ \Delta H^\circ _f \text{ N$_2$H$_4$} + (-285.8\text{ kJ/mol})\right] -\left[ 3(0) + (82.1\text{ kJ/mol})\right] \\ \\ \Delta H^\circ _f \text{ N$_2$H$_4$} & = (-317 + 285.8 + 82.1)\text{ kJ/mol} \\ \\ & = 50.9\text{ kJ/mol} \end{aligned}

In conclusion, our answer is A.

5 0
2 years ago
The partial pressure of CO2 inside a bottle of soft drink is 4.0 atm at 25°C. The solubility of CO2 is 0.12 mol/L. When the bott
navik [9.2K]
We can solve this problem by using Henry's law. 
Henry's law states that the amount of dissolved gas is proportional to its partial pressure.
C=kP
C is <span>the solubility of a gas.
</span><span>k is Henry's law constant.
</span><span>P is the partial pressure of the gas.
</span>We can calculate the constant from the first piece of information and then use Henry's law to calculate solubility in open drink.
0.12=4k
k=0.03
Now we can calculate the solubility in open drink.
C_o=kP_o&#10;
C_o=0.03 \cdot  3\cdot 10^{-4}=0.09\cdot 10^{-4} \frac{mol}{L}
Now we need to convert it to g/L. One mol of CO2 is 44.01<span>g. 
</span>The final answer is:
C_o=0.09\cdot 10^{-4}\cdot 44,01=3.4\cdot 10^{-4} \frac{g}{L} 


4 0
3 years ago
Locate Lithium and oxygen on the periodic table. Briefly explain how these elements might combine to form a compound.
Mars2501 [29]
<span>Lithium atoms have one valence electron, where as oxygen atoms have six. Lithium atoms tend to give up their single valence electrons, and oxygen tends to gain two valence electrons from other atoms, like lithium. They do this so they will have filled valence shells.  hope this answers your question :)</span>
7 0
3 years ago
Read 2 more answers
Given the following equation, what is the correct form of the conversion factor needed to convert the number of moles of O₂ to t
djverab [1.8K]

Answer : The correct option is (c) \frac{2\text{ mole of }Fe_2O_3}{3\text{ mole of }O_2}

Explanation :

The given balanced chemical reaction is,

4Fe(s)+3O_2(g)\rightarrow 2Fe_2O_3(s)

From the balanced chemical reaction, we conclude that

As, 3 moles of O_2 react to give 2 mole of Fe_2O_3

So, 1 mole of O_2 react to give \frac{2\text{ mole of }Fe_2O_3}{3\text{ mole of }O_2} moles of Fe_2O_3

Thus, the conversion factor needed to convert the number of moles of O_2 to the number of moles of Fe_2O_3 produced is \frac{2\text{ mole of }Fe_2O_3}{3\text{ mole of }O_2}

Hence, the correct option is (c) \frac{2\text{ mole of }Fe_2O_3}{3\text{ mole of }O_2}

7 0
3 years ago
Read 2 more answers
Does a large or small body cool faster?
Nataly [62]

Answer:

SO… The larger wire looses heat energy faster, however the smaller wire decreases temperature faster. ... Their surface area is much larger in proportion to their body mass and they lose heat through their skin when it is cold and they gain heat through their skin when it is hot much faster than an adult does.

Explanation:

8 0
3 years ago
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