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Mandarinka [93]
3 years ago
6

The f-xe-f bond angle in the xef2 molecule is approximately ________.

Chemistry
1 answer:
shusha [124]3 years ago
8 0
<span>The f-xe-f bond angle in the xef2 molecule is 90 or 180 degrees. If a hybrid was created their could be a longer measurement. Measurements may very depending on the time and weather .</span>
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Nylon was first synthesised in
galben [10]

Answer:

In 1935

First synthetic fiber produced by man

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3 years ago
What can be absorbed or produced as the result of a chemical reaction???
tia_tia [17]
Heat can be absorbed or produced
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3 years ago
The equilibrium constant, Kp, for the following reaction is 0.497 at 500K.PCl5(g) PCl3(g) + Cl2(g)If an equilibrium mixture of t
Anestetic [448]

<u>Answer:</u> The equilibrium partial pressure of chlorine gas is 0.360 atm

<u>Explanation:</u>

For the given chemical equation:

PCl_5(g)\rightleftharpoons PCl_3(g)+Cl2(g)

The expression of K_p for above reaction follows:

K_p=\frac{p_{Cl_2}\times p_{PCl_3}}{p_{PCl_5}}

We are given:

K_p=0.497\\p_{PCl_3}=0.651atm\\p_{PCl_5}=0.471atm

Putting values in above equation, we get:

0.497=\frac{p_{Cl_2}\times 0.651}{0.471}\\\\p_{Cl_2}=0.360atm

Hence, the equilibrium partial pressure of chlorine gas is 0.360 atm

5 0
3 years ago
What is an atomic weight?
S_A_V [24]
The average weight of an atom of an element, formerly based on the weight of one hydrogen atom taken as a unit or on 1/16 (0.0625) the weight of an oxygen atom, but after 1961 based on 1/12 the weight of the carbon-12 atom.
3 0
3 years ago
A chemistry student weighs out of hypochlorous acid into a volumetric flask and dilutes to the mark with distilled water. He pla
riadik2000 [5.3K]

Answer:

<u><em>Volume of NaOH, aka V2 = 6.32 mL to 3 sig. fig.</em></u>

A chemistry student weighs out 0.0941 g of hypochlorous acid (HClo) into a 250. ml. volumetric flask and dilutes to the mark with distilled water. He plans to titrate the acid with 0.2000 M NaOH solution. Calculate the volume of NaOH solution the student will need to add to reach the equivalence point. Round your answer to 3 significant digits mL.

Explanation:

1 mole HClO = 74.44g

0.0941g = \frac{0.0941}{74.44} = 0.00126 moles

Concentration = no. of moles/volume in L

Hence, Concentration of HClO = 0.00126/ 0.250L

= 0.005M.

C1V1 =C2V2

0.005 × 250 mL = 0.2 × V2

<u><em>Volume of NaOH, aka V2 = 6.32 mL to 3 sig. fig.</em></u>

3 0
3 years ago
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