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Licemer1 [7]
3 years ago
7

HELP PLZ :(((((((

Chemistry
2 answers:
Usimov [2.4K]3 years ago
8 0
 Metamorphic rocks are not easy to make, they are made from rock being exposed to enormous amounts of heat and pressure. Examples of these rock<span> types include marble, slate, gneiss and schist. </span>
dsp733 years ago
8 0

Answer:

c)heat and pressure is the correct answer.

Explanation:

Rock change into a metamorphic rock by heat and pressure.

Metamorphic rocks are formed due to physical and chemical change by heat and pressure of existing rocks. The magma heat warms the enclosing rocks making them change.

The rocks buried underground in the Earth, when they are subjected to heat and pressure these rocks change into metamorphic rocks.The pressure crushes the rock to produce metamorphic rock.

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What is the purpose of writing Shorthand Electron Configuration Using Noble Gases?<br> 30 POINTS!
aivan3 [116]

The noble gas configuration system helps to shorten the total electron configuration by using the symbol for the noble gas that lies before the particular element in the periodic table.  

For example:

Na has atomic number 11

Electron configuration of Na: 1s2 2s2 2p6 3s1

Noble gas electron configuration of Na: [Ne] 3s1

Ne has atomic number 10 and lies before Na in the periodic table.  


6 0
3 years ago
When of a certain molecular compound X are dissolved in of benzene , the freezing point of the solution is measured to be . Calc
puteri [66]

The question is incomplete. Here is the complete question.

When 2.10 g of a certain molecular compound X are dissolved in 65.0 g of benzene (C₆H₆), the freezing point of the solution is measured to be 3.5°C. Calculate the molar mass of X. If you need any additional information on benzene, use only what you find in the ALEKS Data resource. Also, be sure your answer has a unit symbol, and is rounded to 2 significant digits.

Answer: MM = 47.30 g/mol.

Explanation: There is a relationship between <u>freezing</u> <u>point</u> <u>depression</u> and <u>molality</u>. With this last one, is possible to calculate <u>molar</u> <u>mass</u> or molar weight of a compound.

<u>Freezing</u> <u>Point</u> <u>Depression</u> occurs when a solute is added to a solvent: the freezing point of the solvent decreases when a non-volatile solute is incremented.

<u>Molality</u> or <u>molal</u> <u>concentration</u> is a quantity of solute dissolved in a certain mass, in kg, of solvent. Its symbol is m and it's defined as

m=\frac{moles(solute)}{kg(solvent)}

Freezing point depression and molal are related as the following:

\Delta T_{f}=K_{f}.m

where

\Delta T_{f} is freezing point depression of solution

K_{f} is molal freezing point depression constant

m is molality

Now, to determine molar mass, first, find molality of the mixture:

\Delta T_{f}=K_{f}.m

m=\frac{\Delta T_{f}}{K_{f}}

For benzene, constant is 5.12°C/molal. Then

m=\frac{3.5}{5.12}

m = 0.683 molal

Second, knowing the relationship between molal and moles of solute, determine the last one:

m=\frac{moles(solute)}{kg(solvent)}

mol(solute)=m.kg(solvent)

mol(solute) = 0.683(0.065)

mol(solute) = 0.044 mol

The definition for <u>Molar</u> <u>mass</u> is the mass in grams of 1 mol of substance:

n(moles)=\frac{m(g)}{MM(g/mol)}

MM=\frac{m}{n}

In the mixture, there are 0.044 moles of X, so its molecular mass is

MM=\frac{2.1}{0.044}

MM = 47.30 g/mol

The molecular compound X has molecular mass of 47.30 g/mol.

7 0
4 years ago
Calculate ΔH⁰298 (in kJ) for the process P(s) + 5/2 Cl2(g) → PCl5(g) from the following information.
Viefleur [7K]

Answer:

\Delta H_{298}^{0} for the process is -375 kJ

Explanation:

  • Given reaction is a combination of the two given elementary steps.
  • Summation of change in standard enthalpy (\Delta H_{298}^{0})of the two elementary reactions give \Delta H_{298}^{0} of the reaction P(s)+\frac{5}{2}Cl_{2}(g)\rightarrow PCl_{5}(g).

P(s)+\frac{3}{2}Cl_{2}(g)\rightarrow PCl_{3}(g)......\Delta H_{1}=-287kJ

PCl_{3}(g)+Cl_{2}(g)\rightarrow PCl_{5}(g)......\Delta H_{2}=-88kJ

-----------------------------------------------------------------------------------------------------

P(s)+\frac{5}{2}Cl_{2}(g)\rightarrow PCl_{5}(g)

\Delta H_{298}^{0} = \Delta H_{1}+\Delta H_{2}=-287kJ-88kJ=-375kJ

3 0
4 years ago
MATCH UPS - PLEASE HELP ^^photo attachment
Charra [1.4K]

Answer:

14. c

15. e

16. b

17. d

18. a

Explanation:

5 0
3 years ago
Help me with this please !!!
Daniel [21]

militer is the answer

4 0
3 years ago
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