Question

For the reaction, calculate how many moles of the product form when 2.73 mol of h2 completely reacts. assume that there is more than enough of the other reactant. h2(g)+cl2(g)→2hcl(g)

Answer 1

Answer:

$5.46molHCl$

Explanation:

Hello,

In this case, as both of the reactants are completely consumed, one infers that the following stoichiometric relationship leads to the produced moles of the product; hydrochloric acid:

$2.73molH_2*\frac{2molHCl}{1molH_2}=5.46molHCl$

It is important to notice that based on the undergoing chemical reaction, 1 mole of hydrogen is related with 2 moles of hydrochloric acid, that is why he product's moles doubles the hydrogen's moles.

Best regards.

Answer 2

For the calculation of number of moles of HCl that is produced by 2.73 moles of H₂.

Considering the reaction shown below:

H₂ + Cl₂------->2HCl

This can be seen from the reaction that 1 mole of H₂ produce=2 mole of HCl

So , 2.73 mole of H_{2} will produce= 2.73\times 2 mole of HCl

That is 2.73 mole of H_{2} will produce= 5.46 mole of HCl

So 5.46 mole of HCl will be produced by 2.73 mole of H_{2}